A wave of frequency of 10 kHz and amplitude 20 volts is being used to modulate amplitude of carrier wave of frequency 1000 kHz and peak voltage 40 volts. Choose correct option regarding carrier modulated wave.

Option 1 -

Equation of carrier modulated wave is 40{1+0.25 sin 20π*10³t}sin(2π*10⁶t) and modulation index is 0.2

Option 2 -

Equation of carrier modulated wave is 40{1+0.5 sin 20π*10³t}sin(2π*10⁴t) and modulation index is 0.5

Option 3 -

Equation of carrier modulated wave is 40{1+0.5sin 20π*10³t} sin(2π*10⁶t) and modulation index is 2

Option 4 -

Equation of carrier modulated wave is 40{1+0.5 sin 20π*10³t} sin(2π*10⁶t) and depth of modulation is 0.5

0 2 Views | Posted 3 weeks ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    3 weeks ago
    Correct Option - 4


    Detailed Solution:

    µ = A? /A? = 0.5 {A? = 20 volt, A? = 40 volt}
    m (t) = A? sin ω? t {ω? = 2π×10? }
    c (t) = A? sin ω? t {ω? = 2π×10×10³}
    C? (t) = (A? + A? sin ω? t) sin ω? t ⇒ A? {1+ µsin ω? t} sin ω? t

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Amplitude of sidebands = µAc/2
Here µ = Am/Ac = 5/15 = 1/3
Amplitude = (1/3) (15)/2 = 2.5 V
a/10 = 2.5 => a = 25
b/10 = 2.5 => b = 25
a/b = 1

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