Physics Ncert Solutions Class 12th Communication Systems Class 12th Physics

A wave of frequency of 10 kHz and amplitude 20 volts is being used to modulate amplitude of carrier wave of frequency 1000 kHz and peak voltage 40 volts. Choose correct option regarding carrier modulated wave.

Option 1 - <p>Equation of carrier modulated wave is 40{1+0.25 sin 20π×10³t}sin(2π×10⁶t) and modulation index is 0.2<br><br></p>

Option 2 - <p>Equation of carrier modulated wave is 40{1+0.5 sin 20π×10³t}sin(2π×10⁴t) and modulation index is 0.5<br><br></p>

Option 3 - <p>Equation of carrier modulated wave is 40{1+0.5sin 20π×10³t} sin(2π×10⁶t) and modulation index is 2<br><br></p>

Option 4 - <p>Equation of carrier modulated wave is 40{1+0.5 sin 20π×10³t} sin(2π×10⁶t) and depth of modulation is 0.5</p>

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Answered by

Vishal Baghel | Contributor-Level 10

5 months ago

Correct Option - 4

Detailed Solution:

µ = A? /A? = 0.5 {A? = 20 volt, A? = 40 volt}
m (t) = A? sin ω? t {ω? = 2π*10? }
c (t) = A? sin ω? t {ω? = 2π*10*10³}
C? (t) = (A? + A? sin ω? t) sin ω? t ⇒ A? {1+ µsin ω? t} sin ω? t

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Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

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