For VHF signal broadcasting........ km2 of maximum service area will be covered by an antenna tower of height 30m, if the receiving antenna is placed at ground. Let radius of the earth be 6400km. (Round off to the Nearest Integer) (Take π as 3.14)
For VHF signal broadcasting........ km2 of maximum service area will be covered by an antenna tower of height 30m, if the receiving antenna is placed at ground. Let radius of the earth be 6400km. (Round off to the Nearest Integer) (Take π as 3.14)
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1 Answer
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Kindly consider the following figure
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According to question, we can write
Increment in height of tower = h2 – h1 = 500 – 125 = 375 m
Low pass filter will allow low frequency signal to pass while high pass filter allow high frequency to pass through
µ = A? /A? = 0.5 {A? = 20 volt, A? = 40 volt}
m (t) = A? sin ω? t {ω? = 2π×10? }
c (t) = A? sin ω? t {ω? = 2π×10×10³}
C? (t) = (A? + A? sin ω? t) sin ω? t ⇒ A? {1+ µsin ω? t} sin ω? t
Amplitude of sidebands = µAc/2
Here µ = Am/Ac = 5/15 = 1/3
Amplitude = (1/3) (15)/2 = 2.5 V
a/10 = 2.5 => a = 25
b/10 = 2.5 => b = 25
a/b = 1
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