A small bar magnet placed with its axis at <math><msup><mrow><mrow><mn>30</mn></mrow></mrow><mrow><mrow><mo>∘</mo></mrow></mrow></msup></math> with an external field of <math><mn>0.06</mn><mtext></mtext><mi mathvariant="normal">T</mi></math> experiences a torque of <math><mn>0.018</mn><mi mathvariant="normal">N</mi><mi mathvariant="normal">m</mi></math> . The minimum work required to rotate it from its stable to unstable equilibrium position is:

τ? =μ? ×B? ⇒0.018=μ (0.06)sin? 30? ⇒μ=0.6⇒ Work =Uf-Ui⇒2μB⇒7.2×10-2J.

A small bar magnet placed with its axis at&nbsp;<math><msup><mrow><mrow><mn>30</mn></mrow></mrow><mrow><mrow><mo>∘</mo></mrow></mrow></msup></math>&nbsp;with an external field of&nbsp;<math><mn>0.06</mn><mtext></mtext><mi mathvariant="normal">T</mi></math>&nbsp;experiences a torque of&nbsp;<math><mn>0.018</mn><mi mathvariant="normal">N</mi><mi mathvariant="normal">m</mi></math>&nbsp;. The minimum work required to rotate it from its stable to unstable equilibrium position is:

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Physics Class 12th Semiconductor Electronics Physics NCERT Exemplar Solutions Class 12th Chapter Fourteen

A small bar magnet placed with its axis at $30^{\circ}$ with an external field of $0.06 T$ experiences a torque of $0.018 N m$ . The minimum work required to rotate it from its stable to unstable equilibrium position is:

Option 1 -

$11.7 * 10^{- 3} J$

Option 2 -

$9.2 * 10^{- 3} J$

Option 3 -

$7.2 * 10^{- 2} J$

Option 4 -

$6.4 * 10^{- 2} J$

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1 Answer

Answered by

alok kumar singh | Contributor-Level 10

3 months ago

Correct Option - 3

Detailed Solution:

$\overset{?}{τ} = \overset{?}{μ} \times \overset{?}{B}$

$\begin{array}{l} \Rightarrow & 0.018 = μ (0.06) (s i n ? 30^{?}) \\ \Rightarrow & μ = 0.6 \\ \Rightarrow & Work = U_{f} - U_{i} \\ \Rightarrow & 2 μ B \\ \Rightarrow & 7.2 \times 10^{- 2} J . \end{array}$

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A small bar magnet placed with its axis at $30^{\circ}$ with an external field of $0.06 T$ experiences a torque of $0.018 N m$ . The minimum work required to rotate it from its stable to unstable equilibrium position is:

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A small bar magnet placed with its axis at 30∘ with an external field of 0.06T experiences a torque of 0.018Nm . The minimum work required to rotate it from its stable to unstable equilibrium position is:

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A small bar magnet placed with its axis at $30^{\circ}$ with an external field of $0.06 T$ experiences a torque of $0.018 N m$ . The minimum work required to rotate it from its stable to unstable equilibrium position is: