The amplitude of upper and lower side bands of A.M. wave where a carrier signal with frequency 11.21 MHz, peak voltage 15 V is amplitude modulate by a 7.7 kHz sine wave of 5 V amplitude are (a/10) V and ( b/10 ) V respectively. Then the value of a/b is _______.

3 Views|Posted 5 months ago
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1 Answer
V
5 months ago

Amplitude of sidebands = µAc/2
Here µ = Am/Ac = 5/15 = 1/3
Amplitude = (1/3) (15)/2 = 2.5 V
a/10 = 2.5 => a = 25
b/10 = 2.5 => b = 25
a/b = 1

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Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

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