A1 kW signal is transmitted using a communication channel which provides attenuation at the rate of -2dB per km. If the communication channel has a total length of 5 km, the power of the signal received is [gain in  dB=10 log10(p0/pi)]
(a) 900 W    (b) 100 W    (c) 990 W    (d) 1010 W

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10 months ago

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer-b

p = 1kW= 1000W

Attenuation of signal = -2dB/km and total path length = 5km

Gain in dB= 5 * - 2 = - 10 d B

Gain in dB= 10 log (p0/pi)……. (i)

-10=10 log (p0/pi)= -10log (pi/po)

logPi/po=1 = log (pi/po)= log10

pi/p0=10= 1000W= 10p0

p0=100W

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Physics NCERT Exemplar Solutions Class 12th Chapter Fifteen 2025

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