An AC source rated 220 V, 50Hz is connected to a resistor. The time taken by the current to change from its maximum to the rms value is :

Option 1 - <p>25 ms<br>&lt;!--[endif]--&gt;</p>
Option 2 - <p>2.5 ms</p>
Option 3 - <p>0.25 ms</p>
Option 4 - <p>2.5 s</p>
13 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
R
5 months ago
Correct Option - 2
Detailed Solution:

T = 2π√ (l/g) ⇒ g = 4π²l/T²
Percentage error: Δg/g = Δl/l + 2 (ΔT/T) = (0.1/10.0) + 2 (0.005/0.5) = 0.03
Percentage error = (Δg/g) * 100 = 3%
ω = 2πf = 100π rad/s
i_rms = i? /√2
While current changes from its maximum to its rms value, its phase changes by π/4 rad.
t = (π/4)/ω = π/ (4 * 100π) = 2.5 * 10? ³

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