An amplitude modulated wave is as shown in figure. Calculate (i) The percentage modulation, (ii) Peak carrier voltage and (iii) Peak value of information voltage
This is a Long Answer Type Questions as classified in NCERT Exemplar
Maximum voltage = 100/2 = 50V
And minimum voltage = 20/2 = 10V
Percentage modulation= max voltage -min voltage/ max voltage + min voltage
= = 66.67%
Peak career voltage= max voltage+ min voltage/2= 50+10/2=30V
Peak value of information voltage= 66.67/100 30= 20V
<p>This is a Long Answer Type Questions as classified in NCERT Exemplar</p><p>Maximum voltage = 100/2 = 50V</p><p>And minimum voltage = 20/2 = 10V</p><p>Percentage modulation= max voltage -min voltage/ max voltage + min voltage<span contenteditable="false"> <math> <mo>*</mo> <mn>100</mn> <mi> </mi> </math> </span></p><p>= <span contenteditable="false"> <math> <mfrac> <mrow> <mrow> <mn>50</mn> <mo>-</mo> <mn>10</mn> </mrow> </mrow> <mrow> <mrow> <mn>50</mn> <mo>+</mo> <mn>10</mn> </mrow> </mrow> </mfrac> <mo>*</mo> <mn>100</mn> </math> </span>= 66.67%</p><p>Peak career voltage= max voltage+ min voltage/2= 50+10/2=30V</p><p>Peak value of information voltage= 66.67/100 <span contenteditable="false"> <math> <mo>*</mo> </math> </span> 30= 20V</p>
µ = A? /A? = 0.5 {A? = 20 volt, A? = 40 volt} m (t) = A? sin ω? t {ω? = 2π×10? } c (t) = A? sin ω? t {ω? = 2π×10×10³} C? (t) = (A? + A? sin ω? t) sin ω? t ⇒ A? {1+ µsin ω? t} sin ω? t
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