Audio sine waves of 3 kHz frequency are used to amplitude modulate a carrier signal of 1.5 MHz. Which of the following statements are true?
(a) The side band frequencies are 1506 kHz and 1494 kHz

(b) The bandwidth required for amplitude modulation is 6 kHz

(c) The bandwidth required for amplitude modulation is 3 MHz

(d) The side band frequencies are 1503 kHz and 1497 kHz

2 Views|Posted 10 months ago

Asked by Shiksha User

1 Answer

Sort by:

Answered by

Alok Kumar Singh | Contributor-Level 10

10 months ago

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- b, d

Explanation- w_m=3KHz

And w_c= 1.5MHz= 1500KHz

By using these two 1500 $?$ 3= 1503 and 1497

Bandwidth = 2w_m= 2 $* 3$ = 6KHz

Upvote

Similar Questions for you

The TV transmission tower at a particular station has a height of 125 m. For doubling the coverage of its range, the height of the tower should be increased by

Vishal Baghel

According to question, we can write

$d = \sqrt[]{2 h R} \Rightarrow \frac{d_{2}}{d_{1}} = \sqrt[]{\frac{h_{2}}{h_{1}}} \Rightarrow h_{2} = {(\frac{d_{2}}{d_{1}})}^{2} h_{1} = {(\frac{2}{1})}^{2} \times 125 = 500 m$

Increment in height of tower = h₂ – h₁ = 500 – 125 = 375 m

A signal containing multiple frequencies is shown in figure A. It is passed through 2 different filters and then outputs are shown in figure B & C.

Vishal Baghel

Low pass filter will allow low frequency signal to pass while high pass filter allow high frequency to pass through

An antenna is mounted on a 400m tall building. What will be the wavelength of signal that can be radiated effectively by the transmission tower upto a range of 44kg?

Vishal Baghel

$λ > h \Rightarrow λ > 400 m$

Vishal Baghel

µ = A? /A? = 0.5 {A? = 20 volt, A? = 40 volt}
m (t) = A? sin ω? t {ω? = 2π×10? }
c (t) = A? sin ω? t {ω? = 2π×10×10³}
C? (t) = (A? + A? sin ω? t) sin ω? t ⇒ A? {1+ µsin ω? t} sin ω? t

For VHF signal broadcasting........ km² of maximum service area will be covered by an antenna tower of height 30m, if the receiving antenna is placed at ground. Let radius of the earth be 6400km. (Round off to the Nearest Integer) (Take π as 3.14)

Vishal Baghel

Kindly consider the following figure