Choose the correct option relating wavelengths of different parts of electromagnetic wave spectrum:
Choose the correct option relating wavelengths of different parts of electromagnetic wave spectrum:
Option 1 - <p><span contenteditable="false"> <math> <msub> <mrow> <mrow> <mi>λ</mi> </mrow> </mrow> <mrow> <mrow> <mtext>x-rays</mtext> <mtext> </mtext> </mrow> </mrow> </msub> <mo><</mo> <msub> <mrow> <mrow> <mi>λ</mi> </mrow> </mrow> <mrow> <mrow> <mtext>micro waves</mtext> <mtext> </mtext> </mrow> </mrow> </msub> <mo><</mo> <msub> <mrow> <mrow> <mi>λ</mi> </mrow> </mrow> <mrow> <mrow> <mtext>radio waves</mtext> <mtext> </mtext> </mrow> </mrow> </msub> <mo><</mo> <msub> <mrow> <mrow> <mi>λ</mi> </mrow> </mrow> <mrow> <mrow> <mtext>visible</mtext> <mtext> </mtext> </mrow> </mrow> </msub> </math> </span></p>
Option 2 - <p><span contenteditable="false"> <math> <msub> <mrow> <mrow> <mi>λ</mi> </mrow> </mrow> <mrow> <mrow> <mtext>visible</mtext> <mtext> </mtext> </mrow> </mrow> </msub> <mo><</mo> <msub> <mrow> <mrow> <mi>λ</mi> </mrow> </mrow> <mrow> <mrow> <mtext>micro waves</mtext> <mtext> </mtext> </mrow> </mrow> </msub> <mo><</mo> <msub> <mrow> <mrow> <mi>λ</mi> </mrow> </mrow> <mrow> <mrow> <mtext>radio waves</mtext> <mtext> </mtext> </mrow> </mrow> </msub> <mo><</mo> <msub> <mrow> <mrow> <mi>λ</mi> </mrow> </mrow> <mrow> <mrow> <mtext>x-rays</mtext> <mtext> </mtext> </mrow> </mrow> </msub> </math> </span></p>
Option 3 - <p><span contenteditable="false"> <math> <msub> <mrow> <mrow> <mi>λ</mi> </mrow> </mrow> <mrow> <mrow> <mtext>visible</mtext> <mtext> </mtext> </mrow> </mrow> </msub> <mo>></mo> <msub> <mrow> <mrow> <mi>λ</mi> </mrow> </mrow> <mrow> <mrow> <mtext>x-rays</mtext> <mtext> </mtext> </mrow> </mrow> </msub> <mo>></mo> <msub> <mrow> <mrow> <mi>λ</mi> </mrow> </mrow> <mrow> <mrow> <mtext>radio waves</mtext> <mtext> </mtext> </mrow> </mrow> </msub> <mo>></mo> <msub> <mrow> <mrow> <mi>λ</mi> </mrow> </mrow> <mrow> <mrow> <mtext>micro waves</mtext> <mtext> </mtext> </mrow> </mrow> </msub> </math> </span></p>
Option 4 - <p><span contenteditable="false"> <math> <msub> <mrow> <mrow> <mi>λ</mi> </mrow> </mrow> <mrow> <mrow> <mtext>radio waves</mtext> <mtext> </mtext> </mrow> </mrow> </msub> <mo>></mo> <msub> <mrow> <mrow> <mi>λ</mi> </mrow> </mrow> <mrow> <mrow> <mtext>micro waves</mtext> <mtext> </mtext> </mrow> </mrow> </msub> <mo>></mo> <msub> <mrow> <mrow> <mi>λ</mi> </mrow> </mrow> <mrow> <mrow> <mtext>visible</mtext> <mtext> </mtext> </mrow> </mrow> </msub> <mo>></mo> <msub> <mrow> <mrow> <mi>λ</mi> </mrow> </mrow> <mrow> <mrow> <mtext>x-rays</mtext> <mtext> </mtext> </mrow> </mrow> </msub> </math> </span></p>
1 Views|Posted 6 months ago
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1 Answer
A
Answered by
6 months ago
Correct Option - 4
Detailed Solution:
Kindly go through the solution
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According to definition of displacement current, we can write
B0 = 42.9 × 10-9
42.9 Ans
s? = -? + k? ∴ s? = (-? +k? )/√2
I = P/ (4πr²) . (i)
and I = (1/2)ε? E? ²c . (ii)
From (i) and (ii)
P/ (4πr²) = (1/2)ε? E? ²c
E? = √ (2P/ (4πε? r²c) ; E? = √ (9×10? ×2×15)/ (15×15×10? ×3×10? ) = 2×10? ³ V/m
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Physics NCERT Exemplar Solutions Class 12th Chapter Eight 2025
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