Consider sunlight incident on a slit of width 10 4 Å. The image seen through the slit shall
(a) Be a fine sharp slit white in colour at the centre
(b) A bright slit white at the centre diffusing to zero intensities at the edges
(c) A bright slit white at the centre diffusing to regions of different colours
(d) Only be diffused slit white in colour.

3 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
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7 months ago

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- ( a)

Explanation- given width of slit is 10410-10m= 10-6

Wavelength of sunlight varies from 4000A0 to 8000A0

As the width of slit is comparable to that of wavelength, hence diffraction occurs with maxima at centre. So, at the ce

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The angle between the plane of vibration and plane of polarization is 90°.

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Velocity, v? = √ (T? /μ) = √ (20/μ)
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3d = 0.6mm

D = 80cm

= 800mm

Path difference is given by

BP – Andhra Pradesh = Dx

d y D = ( 2 n + 1 ) λ 2   [for Dark fringe at P]

n = 0, for first dark fringe

d y D = λ 2

λ = 2 d D y

= 2 d D × d 2 [ y = d 2 , G i v e n  first dark fringe is observed on the screen directly opposite to one of the slits]

λ = 2 × 0 . 6 × 0 . 6 8 0 0 × 2

λ = 4 5 0 m m

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Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

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