Consider the diffraction pattern for a small pinhole. As the size of the hole is increased
(a) The size decreases
(b) The intensity increases
(c) The size increases
(d) The intensity decreases
Consider the diffraction pattern for a small pinhole. As the size of the hole is increased
(a) The size decreases
(b) The intensity increases
(c) The size increases
(d) The intensity decreases
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1 Answer
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This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer- (a, b)
Explanation- (a) When a decreases w increases. So, size decreases.
(b) Now, light energy is distributed over a small area and intensity?1/Area is decreasing so intensity increases
Similar Questions for you
At lower end
Tension, T? = 2g = 20 N (due to the 2 kg block)
Velocity, v? = √ (T? /μ) = √ (20/μ)
Wavelength, λ? = 6 cm
At upper end
Tension, T? = (2 kg + 6 kg)g = 8g = 80 N (due to the block and the rope)
Velocity, v? = √ (T? /μ) = √ (80/μ) = √4 * √ (20/μ) = 2v?
Since frequency (f) remains the same:
f = v? /λ? = v? /λ?
⇒ λ? = λ? * (v? /v? )
⇒ λ? = λ? * (2v? /v? ) = 2λ?
⇒ λ? = 2 * 6 cm = 12 cm
β = λD / (d? + a? sinωt)
β? - β? = λD/ (d? - a? ) - λD/ (d? + a? )
= λD [ (d? + a? ) - (d? - a? ) / (d? ² - a? ²) ]
= 2λDa? / (d? ² - a? ²)
3d = 0.6mm
D = 80cm
= 800mm
Path difference is given by
BP – Andhra Pradesh = Dx
[for Dark fringe at P]
n = 0, for first dark fringe
first dark fringe is observed on the screen directly opposite to one of the slits]
The distance between two successive bright fringes is fringe width .
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