Figure shows the anode potential vs photo-current graph when photons of 6 eV are incident on cathode in a photoelectric experiment set-up. In the same experimental set-up, if photons of 8 eV and same intensity are incident on cathode, then anode-potential vs photo-current graph will be (assume 100% efficiency of photons to eject photo-electrons in both cases)

 

Maximum wavelength of light source such that photoelectron can be ejected from material of work function 3 eV is

In a photoelectric experiment, frequency f = 1.5f₀ (f₀ : threshold frequency). If the frequency of light is changed to f/2, then photocurrent becomes (intensity of light has doubled)

A photocell works on the principle of

The work function of a metal is w₀ and l is wavelength of incident radiation. There is no emission of photoelectron when

The work function of a metal is w0 and $$ $\lambda$ is wavelength of incident radiation. There is no emission of photoelectron when