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Figure shows the anode potential vs photo-current graph when photons of 6 eV are incident on cathode in a photoelectric experiment set-up. In the same experimental set-up, if photons of 8 eV and same intensity are incident on cathode, then anode-potential vs photo-current graph will be (assume 100% efficiency of photons to eject photo-electrons in both cases)

 

Option 1 -

A

Option 2 -

B

Option 3 -

C

Option 4 -

D

0 66 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    a month ago
    Correct Option - 4


    Detailed Solution:

    Stopping potential increases and number of photons decreases.

    I = h c n p λ t

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