Find the modulation index of an AM wave having 8V variation where maximum amplitude to the wave is 9V.

Option 1 - 0.8

Option 2 - 0.5

Option 3 -  0.2

Option 4 - 0.1

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Answered by

Vishal Baghel | Contributor-Level 10

6 months ago

Correct Option - 1

Detailed Solution:

Modulation Index, $μ = \frac{A_{m}}{A_{C}}$

Variation = $2 A_{m} = 8 \Rightarrow A_{m} = 4 v$

$A_{m} + A_{c} = 9$

$A_{C} = 9 - A_{m} = 5 v$

$∴ μ = \frac{4}{5} = 0.8$

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