For light diverging from a point source,
(a) The wavefront is spherical
(b) The intensity decreases in proportion to the distance squared
(c) The wavefront is parabolic
(d) The intensity at the wavefront does not depend on the distance

0 3 Views | Posted 4 months ago
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    Answered by

    Vishal Baghel | Contributor-Level 10

    4 months ago

    This is a Multiple Choice Questions as classified in NCERT Exemplar

    Answer- (a, b)

    Explanation- Due to the point source light propagates in all directions symmetrically and hence, wavefront will be spherical as shown in the diagram.

    If power of the source is P, then intensity of the source will be I= p/4 π r 2

     where, r is radius of the wavefront at anytime.

Similar Questions for you

A
alok kumar singh

At lower end
Tension, T? = 2g = 20 N (due to the 2 kg block)
Velocity, v? = √ (T? /μ) = √ (20/μ)
Wavelength, λ? = 6 cm

At upper end
Tension, T? = (2 kg + 6 kg)g = 8g = 80 N (due to the block and the rope)
Velocity, v? = √ (T? /μ) = √ (80/μ) = √4 * √ (20/μ) = 2v?

Since frequency (f) remains the same:
f = v? /λ? = v? /λ?
⇒ λ? = λ? * (v? /v? )
⇒ λ? = λ? * (2v? /v? ) = 2λ?
⇒ λ? = 2 * 6 cm = 12 cm

R
Raj Pandey

β = λD / (d? + a? sinωt)
β? - β? = λD/ (d? - a? ) - λD/ (d? + a? )
= λD [ (d? + a? ) - (d? - a? ) / (d? ² - a? ²) ]
= 2λDa? / (d? ² - a? ²)

P
Payal Gupta

I=I0cos230°

=I0 (32)2=34I0 

V
Vishal Baghel

3d = 0.6mm

D = 80cm

= 800mm

Path difference is given by

BP – Andhra Pradesh = Dx

d y D = ( 2 n + 1 ) λ 2   [for Dark fringe at P]

n = 0, for first dark fringe

d y D = λ 2

λ = 2 d D y

= 2 d D × d 2 [ y = d 2 , G i v e n  first dark fringe is observed on the screen directly opposite to one of the slits]

λ = 2 × 0 . 6 × 0 . 6 8 0 0 × 2

λ = 4 5 0 m m

A
alok kumar singh

  Energy     Volume   = M L 2 T - 2 L 3 = M L - 1 T - 2

 The distance between two successive bright fringes is fringe width ( β ) .

β = λ D d = 589 × 10 - 9 × 1.5 0.15 × 10 - 3 = 5.9 m m

 

 

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