For the one-dimensional motion, described by x = t–sint
(a) x (t) > 0 for all t > 0.
(b) v (t) > 0 for all t > 0.
(c) a (t) > 0 for all t > 0.
(d) v (t) lies between 0 and 2.
For the one-dimensional motion, described by x = t–sint
(a) x (t) > 0 for all t > 0.
(b) v (t) > 0 for all t > 0.
(c) a (t) > 0 for all t > 0.
(d) v (t) lies between 0 and 2.
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1 Answer
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This is a multiple choice answer as classified in NCERT Exemplar
(a, d) x= t-sint
Velocity v = dx/dt=
d/dt (t-sint)=
=1-cost
When cost =1, velocity v=0
Vmax=1-costmin = 1- (-1)=2
Vmin =1- (cost)max= 1-1=0
Hence v lies between 0 and 2
Acceleration a=dv/dt=-sint
When v=0 then cost =1
Vmax= 1- (-1)=2, Vmin=1-1=0
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