For two vectors A and B, A B A B + = − is always true when (a) A B = ≠ 0 (b) A&perp; B (c) A B = ≠ 0 and A and B are parallel or anti parallel (d) when either A or B is zero.

This is a Multiple Choice Questions as classified in NCERT ExemplarExplanation- |A+B|=|A-B| A | 2 + B | 2 + 2 A | B | c o s θ = A | 2 + B | 2 - 2 A | B | c o s θ A | 2 + B | 2 + 2 A | B | c o s θ = A | 2 + B | 2 - 2 A | B | c o s θ 4|A|B|cos θ =0|A|2+|B|2cos θ =0A=0 or B=0 so θ = 90 . so A perpendicular B

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Motion in a Plane physics ncert solutions class 11th Physics Class 11th Physics NCERT Exemplar Solutions Class 11th Chapter Four

For two vectors A and B, A B A B + = − is always true when (a) A B = ≠ 0 (b) A⊥ B (c) A B = ≠ 0 and A and B are parallel or anti parallel (d) when either A or B is zero.

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Vishal Baghel | Contributor-Level 10

4 months ago

This is a Multiple Choice Questions as classified in NCERT Exemplar

Explanation- |A+B|=|A-B|

$\sqrt[]{|{A |}^{2} + |{B |}^{2} + 2| A| | B | c o s θ} = \sqrt[]{|{A |}^{2} + |{B |}^{2} - 2| A| | B | c o s θ}$

$|{A |}^{2} + |{B |}^{2} + 2| A| | B | c o s θ$ = $|{A |}^{2} + |{B |}^{2} - 2| A| | B | c o s θ$

4|A|B|cos $θ$ =0

|A|²+|B|²cos $θ$ =0

A=0 or B=0 so $θ = 90$ . so A perpendicular B

This is a Multiple Choice Questions as classified in NCERT ExemplarExplanation- |A+B|=|A-B| <math> <mroot> <mrow> <mrow> <mfenced open="|" close="|" separators="|"> <mrow> <mrow> <msup> <mrow> <mrow> <mi>A</mi> <mo>|</mo> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msup> <mo>+</mo> <mfenced open="|" close="|" separators="|"> <mrow> <mrow> <msup> <mrow> <mrow> <mi>B</mi> <mo>|</mo> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msup> <mo>+</mo> <mn>2</mn> </mrow> </mrow> </mfenced> <mi>A</mi> </mrow> </mrow> </mfenced> <mo>|</mo> <mi>B</mi> <mo>|</mo> <mi>c</mi> <mi>o</mi> <mi>s</mi> <mi>θ</mi> </mrow> </mrow> <mrow></mrow> </mroot> <mo>=</mo> <mroot> <mrow> <mrow> <mfenced open="|" close="|" separators="|"> <mrow> <mrow> <msup> <mrow> <mrow> <mi>A</mi> <mo>|</mo> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msup> <mo>+</mo> <mfenced open="|" close="|" separators="|"> <mrow> <mrow> <msup> <mrow> <mrow> <mi>B</mi> <mo>|</mo> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msup> <mo>-</mo> <mn>2</mn> </mrow> </mrow> </mfenced> <mi>A</mi> </mrow> </mrow> </mfenced> <mo>|</mo> <mi>B</mi> <mo>|</mo> <mi>c</mi> <mi>o</mi> <mi>s</mi> <mi>θ</mi> </mrow> </mrow> <mrow></mrow> </mroot> </math> <math> <mfenced open="|" close="|" separators="|"> <mrow> <mrow> <msup> <mrow> <mrow> <mi>A</mi> <mo>|</mo> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msup> <mo>+</mo> <mfenced open="|" close="|" separators="|"> <mrow> <mrow> <msup> <mrow> <mrow> <mi>B</mi> <mo>|</mo> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msup> <mo>+</mo> <mn>2</mn> </mrow> </mrow> </mfenced> <mi>A</mi> </mrow> </mrow> </mfenced> <mo>|</mo> <mi>B</mi> <mo>|</mo> <mi>c</mi> <mi>o</mi> <mi>s</mi> <mi>θ</mi> </math>  = <math> <mfenced open="|" close="|" separators="|"> <mrow> <mrow> <msup> <mrow> <mrow> <mi>A</mi> <mo>|</mo> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msup> <mo>+</mo> <mfenced open="|" close="|" separators="|"> <mrow> <mrow> <msup> <mrow> <mrow> <mi>B</mi> <mo>|</mo> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msup> <mo>-</mo> <mn>2</mn> </mrow> </mrow> </mfenced> <mi>A</mi> </mrow> </mrow> </mfenced> <mo>|</mo> <mi>B</mi> <mo>|</mo> <mi>c</mi> <mi>o</mi> <mi>s</mi> <mi>θ</mi> </math> 4|A|B|cos <math> <mi>θ</mi> </math> =0|A|2+|B|2cos <math> <mi>θ</mi> </math> =0A=0 or B=0 so <math> <mi>θ</mi> <mo>=</mo> <mn>90</mn> </math> . so A perpendicular B

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For two vectors A and B, A B A B + = − is always true when (a) A B = ≠ 0 (b) A⊥ B (c) A B = ≠ 0 and A and B are parallel or anti parallel (d) when either A or B is zero.

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