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Moment of Inertia Physics System of Particles and Rotational Motion Physics Class 11th

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.

Assertion A: Moment of inertia of a circular disc 'M' and radius 'R' about X, Y axes (passing through its plane) and Z-axis which is perpendicular to its plane were found to be I?, I? & I? respectively. The respective radii of gyration about all the three axes will be the same.

Reason R: A rigid body making rotational motion has fixed mass and shape.

In the light of the above statements, choose the most appropriate answer from the options given below:

Option 1 -

A is correct but R is not correct.

Option 2 -

Both A and R are correct and R is the correct explanation of A.

Option 3 -

Both A and R are correct but R is NOT the correct explanation of A.

Option 4 -

A is not correct but R is correct

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$I = (\frac{2}{5} M R^{2} + M R^{2}) \times 2$

$= \frac{14}{5} \times 2 \times \frac{9}{16}$

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The momentum of inertia of a uniform thin rod about a perpendicular axis passing through on end is I1. The same rod is into a ring and its moment of inertia about a diameter is I2. If $\frac{I_{1}}{I_{2}} i s \frac{X π^{2}}{3},$ $\frac{_{}}{_{}} \frac{^{}}{}$ then the value of x will be__________.

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According to question, we can write

$l = 2 π r \Rightarrow r = \frac{l}{2 π}$

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