<p><strong>If <math><mrow><mover accent="true"><mrow><mi>A</mi></mrow><mo stretchy="true">¯</mo></mover><mo>=</mo><mrow><mo>(</mo><mrow><mn>2</mn><mover accent="true"><mi>i</mi><mo>^</mo></mover><mo>+</mo><mn>3</mn><mover accent="true"><mi>j</mi><mo>^</mo></mover><mo>−</mo><mover accent="true"><mi>k</mi><mo>^</mo></mover></mrow><mo>)</mo></mrow><mi>m</mi><mtext> </mtext><mtext> </mtext><mi>a</mi><mi>n</mi><mi>d</mi><mtext> </mtext><mtext> </mtext><mover accent="true"><mrow><mi>B</mi></mrow><mo stretchy="true">→</mo></mover><mo>=</mo><mrow><mo>(</mo><mrow><mover accent="true"><mi>i</mi><mo>^</mo></mover><mo>+</mo><mn>2</mn><mover accent="true"><mi>j</mi><mo>^</mo></mover><mo>+</mo><mn>2</mn><mover accent="true"><mi>k</mi><mo>^</mo></mover></mrow><mo>)</mo></mrow><mi>m</mi><mo>.</mo></mrow></math> The magnitude of component of vector <math><mrow><mover accent="true"><mrow><mi>A</mi></mrow><mo stretchy="true">→</mo></mover></mrow></math> along vector <math><mrow><mover accent="true"><mrow><mi>B</mi></mrow><mo stretchy="true">→</mo></mover></mrow></math> will be________m.</strong></p>

Component of A→ along B→ = A→.B→|B→|= 2

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Physics Class 12th Physics NCERT Exemplar Solutions Class 12th Chapter Four Motion in a Plane

If $\bar{A} = (2 \hat{i} + 3 \hat{j} - \hat{k}) m a n d \vec{B} = (\hat{i} + 2 \hat{j} + 2 \hat{k}) m .$ The magnitude of component of vector $\vec{A}$ along vector $\vec{B}$ will be________m.

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alok kumar singh | Contributor-Level 10

2 months ago

Component of $\vec{A}$ along $\vec{B}$ = $\frac{\vec{A} . \vec{B}}{| \vec{B} |}$

= 2

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If $\bar{A} = (2 \hat{i} + 3 \hat{j} - \hat{k}) m a n d \vec{B} = (\hat{i} + 2 \hat{j} + 2 \hat{k}) m .$ The magnitude of component of vector $\vec{A}$ along vector $\vec{B}$ will be________m.

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If $\bar{A} = (2 \hat{i} + 3 \hat{j} - \hat{k}) m a n d \vec{B} = (\hat{i} + 2 \hat{j} + 2 \hat{k}) m .$ The magnitude of component of vector $\vec{A}$ along vector $\vec{B}$ will be________m.