<p><strong>If the initial velocity in horizontal direction of a projectile is unit vector <math><mrow><mover accent="true"><mi>i</mi><mo>^</mo></mover></mrow></math> and the equation of trajectory is y = 5x(1 – x). The y component vector of the initial velocity is ________ <math><mrow><mover accent="true"><mi>j</mi><mo>^</mo></mover></mrow></math> .</strong></p>

y = x5 (1 - x) = x tanθ (1−xR)tan = 5, R = 1sinθ=526, cosθ=126R=u2sin2θg=1⇒u2=26⇒u=26m/sy - component of initial velocity= u sinθ = =26×526= 5 m/s

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Physics Class 12th Motion in a Plane Physics NCERT Exemplar Solutions Class 12th Chapter Four

If the initial velocity in horizontal direction of a projectile is unit vector $\hat{i}$ and the equation of trajectory is y = 5x(1 – x). The y component vector of the initial velocity is ________ $\hat{j}$ .

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Vishal Baghel | Contributor-Level 10

2 months ago

y = x5 (1 - x) = x tanθ $(1 - \frac{x}{R})$

tan = 5, R = 1

$s i n θ = \frac{5}{\sqrt[]{26}}, c o s θ = \frac{1}{\sqrt[]{26}}$

$R = \frac{u^{2} s i n 2 θ}{g} = 1$

$\Rightarrow u^{2} = 26 \Rightarrow u = \sqrt[]{26} m / s$

y - component of initial velocity

= u sinθ

= $= \sqrt[]{26} \times \frac{5}{\sqrt[]{26}}$

= 5 m/s

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If the initial velocity in horizontal direction of a projectile is unit vector $\hat{i}$ and the equation of trajectory is y = 5x(1 – x). The y component vector of the initial velocity is ________ $\hat{j}$ .

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If the initial velocity in horizontal direction of a projectile is unit vector $\hat{i}$ and the equation of trajectory is y = 5x(1 – x). The y component vector of the initial velocity is ________ $\hat{j}$ .