Two vectors have equal magnitudes. If magnitude of is equal to two times the magnitude of then the angle between will be:
Two vectors have equal magnitudes. If magnitude of is equal to two times the magnitude of then the angle between will be:
Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>s</mi> <mi>i</mi> <msup> <mrow> <mi>n</mi> </mrow> <mrow> <mo>−</mo> <mn>1</mn> </mrow> </msup> <mrow> <mo>(</mo> <mrow> <mfrac> <mrow> <mn>3</mn> </mrow> <mrow> <mn>5</mn> </mrow> </mfrac> </mrow> <mo>)</mo> </mrow> </mrow> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>s</mi> <mi>i</mi> <msup> <mrow> <mi>n</mi> </mrow> <mrow> <mo>−</mo> <mn>1</mn> </mrow> </msup> <mrow> <mo>(</mo> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>3</mn> </mrow> </mfrac> </mrow> <mo>)</mo> </mrow> </mrow> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>c</mi> <mi>o</mi> <msup> <mrow> <mi>s</mi> </mrow> <mrow> <mo>−</mo> <mn>1</mn> </mrow> </msup> <mrow> <mo>(</mo> <mrow> <mfrac> <mrow> <mn>3</mn> </mrow> <mrow> <mn>5</mn> </mrow> </mfrac> </mrow> <mo>)</mo> </mrow> </mrow> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>c</mi> <mi>o</mi> <msup> <mrow> <mi>s</mi> </mrow> <mrow> <mo>−</mo> <mn>1</mn> </mrow> </msup> <mrow> <mo>(</mo> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>3</mn> </mrow> </mfrac> </mrow> <mo>)</mo> </mrow> </mrow> </math> </span></p>
3 Views|Posted 6 months ago
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1 Answer
A
Answered by
6 months ago
Correct Option - 3
Detailed Solution:
Given A = B
Squaring equation (1) both side.
2A2 + 2A2 cosq = 4 (2A2 – 2A2 cosq)
2A2 + 2A2 cosq = 8A2 – 8A2 cosq
10A2 cosq = 6A2
cosq =
q = cos-1 (3/5)
Similar Questions for you
Component of along =
= 2
y = x5 (1 - x) = x tanθ
tan = 5, R = 1
y - component of initial velocity
= u sinθ
=
= 5 m/s
H1 = H2
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Physics NCERT Exemplar Solutions Class 12th Chapter Four 2025
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