Two vectors A a n d B  have equal magnitudes. If magnitude of   A + B is equal to two times the magnitude of   A B , then the angle between A a n d B  will be:

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>s</mi> <mi>i</mi> <msup> <mrow> <mi>n</mi> </mrow> <mrow> <mo>−</mo> <mn>1</mn> </mrow> </msup> <mrow> <mo>(</mo> <mrow> <mfrac> <mrow> <mn>3</mn> </mrow> <mrow> <mn>5</mn> </mrow> </mfrac> </mrow> <mo>)</mo> </mrow> </mrow> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>s</mi> <mi>i</mi> <msup> <mrow> <mi>n</mi> </mrow> <mrow> <mo>−</mo> <mn>1</mn> </mrow> </msup> <mrow> <mo>(</mo> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>3</mn> </mrow> </mfrac> </mrow> <mo>)</mo> </mrow> </mrow> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>c</mi> <mi>o</mi> <msup> <mrow> <mi>s</mi> </mrow> <mrow> <mo>−</mo> <mn>1</mn> </mrow> </msup> <mrow> <mo>(</mo> <mrow> <mfrac> <mrow> <mn>3</mn> </mrow> <mrow> <mn>5</mn> </mrow> </mfrac> </mrow> <mo>)</mo> </mrow> </mrow> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>c</mi> <mi>o</mi> <msup> <mrow> <mi>s</mi> </mrow> <mrow> <mo>−</mo> <mn>1</mn> </mrow> </msup> <mrow> <mo>(</mo> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>3</mn> </mrow> </mfrac> </mrow> <mo>)</mo> </mrow> </mrow> </math> </span></p>
3 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
A
6 months ago
Correct Option - 3
Detailed Solution:

| A + B | = 2 | A B |

Given A = B

Squaring equation (1) both side.

| A + B | 2 = ( 2 | A B | ) 2

A 2 + B 2 + 2 A . B = 4 ( A 2 + B 2 2 A . B )

2A2 + 2A2 cosq = 4 (2A2 – 2A2 cosq)

   2A2 + 2A2 cosq = 8A2 – 8A2 cosq

 10A2 cosq = 6A2

cosq =   3 5

 q = cos-1 (3/5)

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Physics NCERT Exemplar Solutions Class 12th Chapter Four 2025

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