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Physics NCERT Exemplar Solutions Class 12th Chapter Six Physics Class 12th Physics NCERT Exemplar Solutions Class 12th Chapter Four Motion in a Plane

Time period of a simple pendulum in a stationary lift is ‘T’. If the lift accelerated with $\frac{g}{6}$ vertically upwards then the time period will be:

(Where g = acceleration due to gravity)

Option 1 -

$\sqrt[]{\frac{6}{5}} T$

Option 2 -

$\sqrt[]{\frac{5}{6}} T$

Option 3 -

$\sqrt[]{\frac{6}{7}} T$

Option 4 -

$\sqrt[]{\frac{5}{6}} T$

2 Views | Posted 2 months ago

Asked by Shiksha User

1 Answer

Answered by

Payal Gupta | Contributor-Level 10

2 months ago

Correct Option - 3

Detailed Solution:

$g_{e f f} = g + a$

$= g + \frac{g}{6}$

$= \frac{7 g}{6}$

$T' = 2 π \sqrt[]{\frac{l}{g_{e f f}}}$

$T' = \sqrt[]{\frac{6}{7}} T$

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Time period of a simple pendulum in a stationary lift is ‘T’. If the lift accelerated with $\frac{g}{6}$ vertically upwards then the time period will be:

(Where g = acceleration due to gravity)

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Time period of a simple pendulum in a stationary lift is ‘T’. If the lift accelerated with g6 vertically upwards then the time period will be: (Where g = acceleration due to gravity)

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Time period of a simple pendulum in a stationary lift is ‘T’. If the lift accelerated with $\frac{g}{6}$ vertically upwards then the time period will be:

(Where g = acceleration due to gravity)