If each diode in figure has a forward bias resistance of 25 Ω and infinite resistance in reverse bias, what will be the values of the currents I1, I2, I3and I4?

0 2 Views | Posted 4 months ago
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    Answered by

    alok kumar singh | Contributor-Level 10

    4 months ago

    This is a Long Answer Type Questions as classified in NCERT Exemplar

    forward biased resistance = 25ohm

    Reverse biased resistance = infinity

    As CD branch is reverse biased having infinite resistance.

    So I3= 0

    Resistance in branch AB= 25+125= 150 ohm (R1)

    Resistance in branch EF= 25+125= 150 ohm (R2)

    They both are in parallel

     So 1 R = 1 R 1 + 1 R 2 = 1 150 + 1 150 = 2 150

    R= 75ohm

    So total resistance = 25+75= 100ohm

    Current = V/R= 5/100=0.05A

    I1=I2+I3+I4

    I1=I4+I2

    Here the resistance R1 and R2 is same

    I4=I2

    I1= 2I2

    I2= I1/2=0.05/2=0.025A

    I4= 0.025A

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