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Physics NCERT Exemplar Solutions Class 12th Chapter Fourteen Physics Class 12th Semiconductor Electronics

If each diode in figure has a forward bias resistance of 25 Ω and infinite resistance in reverse bias, what will be the values of the currents I₁, I₂, I₃and I₄?

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alok kumar singh | Contributor-Level 10

4 months ago

This is a Long Answer Type Questions as classified in NCERT Exemplar

forward biased resistance = 25ohm

Reverse biased resistance = infinity

As CD branch is reverse biased having infinite resistance.

So I₃= 0

Resistance in branch AB= 25+125= 150 ohm (R₁)

Resistance in branch EF= 25+125= 150 ohm (R₂)

They both are in parallel

So $\frac{1}{R} = \frac{1}{R_{1}} + \frac{1}{R_{2}} = \frac{1}{150} + \frac{1}{150} = \frac{2}{150}$

R= 75ohm

So total resistance = 25+75= 100ohm

Current = V/R= 5/100=0.05A

I₁=I₂+I₃+I₄

I₁=I₄+I₂

Here the resistance R₁ and R₂ is same

I₄=I₂

I₁= 2I₂

I₂= I₁/2=0.05/2=0.025A

I₄= 0.025A

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If each diode in figure has a forward bias resistance of 25 Ω and infinite resistance in reverse bias, what will be the values of the currents I₁, I₂, I₃and I₄?

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If each diode in figure has a forward bias resistance of 25 Ω and infinite resistance in reverse bias, what will be the values of the currents I₁, I₂, I₃and I₄?