If t = x + 4 , t h e n ( d x d t ) t = 4 i s :

t=x+4 then dtdx=12x∴ (dxdt)t=4= (2x)t=4= [2 (t−4)]at t=4 = 0

If t = $\sqrt[]{x} + 4, t h e n {(\frac{d x}{d t})}_{t = 4} i s :$

Option 1 -  4

Option 2 - zero

Option 3 - 8

Option 4 - 16

2 Views|Posted 6 months ago

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Answered by

Vishal Baghel | Contributor-Level 10

6 months ago

Correct Option - 2

Detailed Solution:

$t = \sqrt[]{x} + 4$

then $\frac{d t}{d x} = \frac{1}{2 \sqrt[]{x}} ∴ {(\frac{d x}{d t})}_{t = 4} = {(2 \sqrt[]{x})}_{t = 4} = {[2 (t - 4)]}_{a t t = 4}$

= 0

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