In a Young's double-slit experiment, the source is white light. One of the holes is covered by a red filter and another by a blue filter. In this case,
(a) There shall be alternate interference patterns of red and blue
(b) There shall be an interference pattern for red distinct from that for blue
(c) There shall be no interference fringes
(d) There shall be an interference pattern for red mixing with one for blue
In a Young's double-slit experiment, the source is white light. One of the holes is covered by a red filter and another by a blue filter. In this case,
(a) There shall be alternate interference patterns of red and blue
(b) There shall be an interference pattern for red distinct from that for blue
(c) There shall be no interference fringes
(d) There shall be an interference pattern for red mixing with one for blue
This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer – (c)
Explanation- For the interference pattern to be formed on the screen, the sources should be coherent and emits lights of same frequency and wavelength. In a Young's double-slit experiment, when one of the holes is covered
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The angle between the plane of vibration and plane of polarization is 90°.
At lower end
Tension, T? = 2g = 20 N (due to the 2 kg block)
Velocity, v? = √ (T? /μ) = √ (20/μ)
Wavelength, λ? = 6 cm
At upper end
Tension, T? = (2 kg + 6 kg)g = 8g = 80 N (due to the block and the rope)
Velocity, v? = √ (T? /μ) = √ (80/μ) = √4 * √ (20/μ) = 2v?
Since frequency (f) remains the same:
f = v?
β = λD / (d? + a? sinωt)
β? - β? = λD/ (d? - a? ) - λD/ (d? + a? )
= λD [ (d? + a? ) - (d? - a? ) / (d? ² - a? ²) ]
= 2λDa? / (d? ² - a? ²)
3d = 0.6mm
D = 80cm
= 800mm
Path difference is given by
BP – Andhra Pradesh = Dx
[for Dark fringe at P]
n = 0, for first dark fringe
first dark fringe is observed on the screen directly opposite to one of the slits]
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Physics Ncert Solutions Class 12th 2023
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