In one dimensional motion, instantaneous speed v satisfies 0 ≤ v < v0.
(a) The displacement in time T must always take non-negative values.
(b) The displacement x in time T satisfies – voT < x < voT.
(c) The acceleration is always a non-negative number.
(d) The motion has no turning points.
In one dimensional motion, instantaneous speed v satisfies 0 ≤ v < v0.
(a) The displacement in time T must always take non-negative values.
(b) The displacement x in time T satisfies – voT < x < voT.
(c) The acceleration is always a non-negative number.
(d) The motion has no turning points.
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1 Answer
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This is a multiple choice answer as classified in NCERT Exemplar
(b) For maximum and minimum displacement we have to keep in mind the magnitude and direction of maximum velocity.
As maximum velocity in positive direction is vo maximum velocity in opposite direction is also vo.
Maximum displacement in one direction = voT
Maximum displacement in opposite direction=-voT
Hence -voT
oT
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Please find the solution below:
[h] = ML2T-1
[E] = ML2T-2
[V] = ML2T-2C-1
[P] = MLT-1
According to question, we can write
10 =
Average speed
(d) Initial velocity
Final velocity
Change in velocity
Momentum gain is along
Force experienced is along
Force experienced is in North-East direction.
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