In the circuit diagram find the value of R_c

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Alok Kumar Singh | Contributor-Level 10

9 months ago

This is a Long Answer Type Questions as classified in NCERT Exemplar

Explanation- I_E=I_C+I_Band I_c= $β I_{B}$

I_cRc+V_CE+I_ER_E=V_CC

RI_B+V_BE+I_ER_E=V_cc

I_E=I_c= $β I_{B}$

From above equation

(R+ $β R$ _E)I_B=V_CC-V_BE

I_B= $\frac{V_{C C} - V_{B E}}{R + β R_{E}} = \frac{12 - 0.5}{80 + 1.2 * 100} = \frac{11.5}{200}$

( $R_{C} + R_{E}$ )= $\frac{V_{C E} - V_{B E}}{I_{C}}$

( $R_{C} + R_{E}$ )=1.56

Rc=1.56-1=0.56kohm

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In the circuit diagram find the value of Rc