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Physics NCERT Exemplar Solutions Class 12th Chapter Fourteen Physics Class 12th Semiconductor Electronics

In the circuit shown in figure, when the input voltage of the base resistance is 10 V, V_BEis zero and V_CE is also zero. Find the values of I_B, I_C and β .

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alok kumar singh | Contributor-Level 10

4 months ago

This is a Long Answer Type Questions as classified in NCERT Exemplar

Explanation- voltage across R_B= 10V

Resistance R_B= 400kohm

V_BE= 0, V_CE= 0, R_c=3kohm

I_B= voltage /R_B= 10/400 $\times$ 10³= 25 $\times$ 10^-6A

Voltage across R_c= 10V

I_c=voltage/R_c= 10/3 $\times$ 10³= 3.33 $\times$ 10^-3

$β = \frac{I_{c}}{I_{B}} = \frac{3.33 \times 10^{- 3}}{25 \times 10^{- 6}} = 133$

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In the circuit shown in figure, when the input voltage of the base resistance is 10 V, V_BEis zero and V_CE is also zero. Find the values of I_B, I_C and β .

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In the circuit shown in figure, when the input voltage of the base resistance is 10 V, VBEis zero and VCE is also zero. Find the values of IB, IC and β .

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In the circuit shown in figure, when the input voltage of the base resistance is 10 V, V_BEis zero and V_CE is also zero. Find the values of I_B, I_C and β .