Light with an energy flux of 20 W/cm2 falls on a non-reflecting surface at normal incidence. If the surface has an area of 30 cm2, the total momentum delivered (for complete absorption) during 30 min is

(a) 36 x 10-5 kg-m/s               

(b) 36 x 10-4 kg-m/s

(c) 108 x 104 kg-m/s               

(d) 1.08 x 10kg-m/s

0 2 Views | Posted 4 months ago
Asked by Shiksha User

  • 1 Answer

  • P

    Answered by

    Payal Gupta | Contributor-Level 10

    4 months ago

    This is a multiple choice answer as classified in NCERT Exemplar

    (b) as we know momentum = energy transferred/speed of light

    = 20 × 30 × 30 × 60 3 × 10 8 = 36 × 10-4kgms-1

    Momentum of reflected light =0

    So momentum delivered is = 36 × 10-4kgms-1

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