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Maths NCERT Exemplar Solutions Class 11th Chapter Eleven Moment of Inertia Physics System of Particles and Rotational Motion Physics Class 11th

Moment of inertia (M.I) of four bodies, having same mass and radius, and reported as:

I₁ = M.I. of thin circular ring about its diameter

I₂ = M.I. of circular disc about an axis perpendicular to disc and going through the centre,

I₃ = M.I. of solid cylinder about its axis and

I₄ = M.I. of solid sphere about its diameter.

Option 1 -

I₁ + I₃ < I₂ + I₄

Option 2 -

I₁ = I₂ = I₃ < I₄

Option 3 -

I₁ = I₂ = I₃ > I₄

Option 4 -

$I_{1} + I_{2} = I_{3} + \frac{5}{2} I_{4}$

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Answered by

alok kumar singh | Contributor-Level 10

a month ago

Correct Option - 1

Detailed Solution:

$l_{1} = \frac{1}{2} m r^{2}$

$\begin{array}{l} l_{2} = \frac{1}{2} m r^{2} \\ l_{3} = \frac{1}{2} m r^{2} \\ l_{4} = \frac{2}{5} m r^{2} \end{array}$

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