Refer to the graphs in Fig 3.1. Match the following.
Graph Characteristic
(a) (i) has v > 0 and a < 0 throughout.
(b) (ii) has x > 0 throughout and has a point with v = 0 and a point with a = 0.
(c) (iii) has a point with zero displacement for t > 0.
(d) (iv) has v < 0 and a > 0.

Refer to the graphs in Fig 3.1. Match the following.
Graph Characteristic
(a) (i) has v > 0 and a < 0 throughout.
(b) (ii) has x > 0 throughout and has a point with v = 0 and a point with a = 0.
(c) (iii) has a point with zero displacement for t > 0.
(d) (iv) has v < 0 and a > 0.
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1 Answer
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This is a short answer type question as classified in NCERT Exemplar
We have to analyse slope of each curve i.e= dx/dt . for peak values dx/dt will be zero as x is maximum at peak points.
For graph (a) there is appoint for which displacement is zero so a matches with (iii)
In graph b, x is positive throughout and at point B, V=dx/dt=0
Since at point of curvature changes a=0, so b matches with (ii)
displacement is zero in only first graph so it matches with the (iii) point.
And slope of d graph v=dx/dt is positive so v>0 so acceleration will be negative so matches with I but in graph c it matches with iv as its slope is negative.
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