Show that average value of radiant flux density S over a single period T is given by S= .
Show that average value of radiant flux density S over a single period T is given by S= .
This is a short answer type question as classified in NCERT Exemplar
As we know radiant flux density S= (E )= c2 0(E )
Suppose electromagnetic waves be propagating along x-axis. The electric field vector of
Electromagnetic wave be along y-axis and magnetic field vector be along z-axis. Therefore,
E
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According to definition of displacement current, we can write
B0 = 42.9 × 10-9
42.9 Ans
s? = -? + k? ∴ s? = (-? +k? )/√2
I = P/ (4πr²) . (i)
and I = (1/2)ε? E? ²c . (ii)
From (i) and (ii)
P/ (4πr²) = (1/2)ε? E? ²c
E? = √ (2P/ (4πε? r²c) ; E? = √ (9×10? ×2×15)/ (15×15×10? ×3×10? ) = 2×10? ³ V/m
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Physics Ncert Solutions Class 12th 2023
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