The cut-off voltage of the diodes (shown in figure) in forward bias is 0.6 V. The current through the resister of 40 Ω  is………….mA

 

8 Views|Posted 7 months ago
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7 months ago

D1 forward biased

D2 Reversed biased

So, current will flow through only  D1

l = ( 1 0 . 6 ) v ( 6 0 + 4 0 ) Ω = 0 . 4 1 0 0                

= 4 * 10-3 A

= 4mA

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