The cut-off voltage of the diodes (shown in figure) in forward bias is 0.6 V. The current through the resister of 40
is………….mA
The cut-off voltage of the diodes (shown in figure) in forward bias is 0.6 V. The current through the resister of 40 is………….mA
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1 Answer
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D1 → forward biased
D2 → Reversed biased
So, current will flow through only D1
= 4 × 10-3 A
= 4mA
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