The displacement current of 4.425 μ A  is developed in the space between the plates of parallel plate capacitor when voltage is changing at a rate of 106 Vs-1. The area of each plate of the capacitor is 40 cm2. The distance between each plate of the capacitor is x * 10-3. The value of x is,

(Permittivity of free space, E 0 = 8 . 8 5 * 1 0 1 2 C 2 N 1 m 2 ) _ _ _ _ _ _ _ _ _ _  

3 Views|Posted 6 months ago
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6 months ago

According to definition of displacement current, we can write

Id=ε0d? dt=ε0d (ES)dt=ε0d (VlS)dt=ε0Sl (dVdt)

l=8.85*1012*40*104*1064.425*1068*103m

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Physics Ncert Solutions Class 12th 2023

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