The intensity of the light from a bulb incident on a surface is 0.22 W/m2. The amplitude of the magnetic field in this light – wave is__________ * 10-9 T.
(Given : Permittivity of vacuum speed of light in vacuum c = 3 * 108 ms-1)
The intensity of the light from a bulb incident on a surface is 0.22 W/m2. The amplitude of the magnetic field in this light – wave is__________ * 10-9 T.
(Given : Permittivity of vacuum speed of light in vacuum c = 3 * 108 ms-1)
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According to definition of displacement current, we can write
B0 = 42.9 × 10-9
42.9 Ans
s? = -? + k? ∴ s? = (-? +k? )/√2
I = P/ (4πr²) . (i)
and I = (1/2)ε? E? ²c . (ii)
From (i) and (ii)
P/ (4πr²) = (1/2)ε? E? ²c
E? = √ (2P/ (4πε? r²c) ; E? = √ (9×10? ×2×15)/ (15×15×10? ×3×10? ) = 2×10? ³ V/m
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Physics NCERT Exemplar Solutions Class 12th Chapter Eight 2025
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