The speed verses time graph for a particle is shown in the figure. The distance travelled (in $m$ ) by the particle during the time interval $t = 0$ to $t = 5 s$ will be $\dots .$ .

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Alok Kumar Singh | Contributor-Level 10

6 months ago

Sol.

$\Rightarrow n_{1} T_{1} + n_{2} T_{2} = n T$

$\Rightarrow (0.1) (200) + (0.05) (400) = (0.15) T$

$\Rightarrow T = 266.67$

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Two balls A and B placed at the top of 180m tall tower. Ball A is from the top at t = 0s. Ball B is thrown vertically down with an initial velocity ‘u’ at t = 2s. After a certain time, both balls meet 100m above the ground. Find the value of ‘u’ in ms^-¹.

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Alok Kumar Singh

Let 't' be the time taken by B to meat A. &n

Payal Gupta

Let ‘t’ be the time taken by B to meat

for A, u = 0

t = [2 + t]

h = 80m

a = 10 m/sec²

h = ut + $\frac{1}{2} a t^{2}$

80 = 0 × t + $\frac{1}{2} (10) {(2 + t)}^{2}$

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t + 2 = 4

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Now for B

h = ut + $\frac{1}{2} a t^{2}$

$\Rightarrow 80 = u \times 2 + \frac{1}{2} \times 10 t^{2}$

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80 = 2u + 20

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The speed verses time graph for a particle is shown in the figure. The distance travelled (in m ) by the particle during the time interval t = 0 to t = 5 s will be … . .