Two particles A1and A2 of masses m1 , m2 ( m1> m2) have the same de-Broglie
Then,
(a) their momenta are the same
(b) their energies are the same
(c) energy of A1 is less than the energy of A2
(d) energy of A1 is more than the energy of A2
Answer-(a,c)
Two particles A1and A2 of masses m1 , m2 ( m1> m2) have the same de-Broglie
Then,
(a) their momenta are the same
(b) their energies are the same
(c) energy of A1 is less than the energy of A2
(d) energy of A1 is more than the energy of A2
Answer-(a,c)
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1 Answer
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This is a Multiple Choice Questions as classified in NCERT Exemplar
Explanation- as debroglie wavelength is
P=h/
P1/p2=
If wavelength are equal then ratio is 1:1 so P1=P2
E= 1/2mv2= p2/2m
E inversely proportional to m
So = <1
E1
2
Similar Questions for you
Based on theory
z² × (13.6) (1 - ¼) = 3 × (13.6)
z = 2 . (i)
h/√2mk? = (1/2.3) × h/√2mk?
=> k? = (2.3)²k? = 5.25k? (ii)
Now, k? = E? - Φ
k? = E? - Φ = z²E? - Φ
∴ k? /k? = (10.2 - Φ)/ (4 × 10.2 - Φ) = 1/5.25
=> Φ = 3eV
- (i)
- (ii)
from (i) & (ii)
ev
hu = hu0 + K.E
Cases u = 2u0
h2u0 = hu0 + K.E1
K.E1 = hu0
- (1)
Now, cases 2
h 5u0 = hu0 + k.E2
k.E2 = 4hu0
v2 =
v2 = 2v1
This is a Short Answer Type Questions as classified in NCERT Exemplar
Sol:
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