Two particles are projected in air with speed vo at angles θ1 and θ2 (both acute) to the horizontal, respectively. If the height reached by the first particle is greater than that of the second, then tick the right choices

(a) Angle of projection : q1 > q2

(b) Time of flight : T1 > T2

(c) Horizontal range : R1 > R2

(d) Total energy : U1 > U2 .

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Vishal Baghel | Contributor-Level 10

7 months ago

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- a,b,c

Explanation – H= $\frac{u^{2} {s i n}^{2} θ}{2 g}$

H₁=V_o²sin^{2 $θ$}₁/2g , H₂=V_o²sin^{2 $θ$}₂/2g

H₁>H₂

V_o²sin^{2 $θ$}₁/2g= V_o²sin^{2 $θ$}₂/2g

Sin^{2 $θ$}₁>sin^{2 $θ$}₂

Sin^{2 $θ$}₁ – sin² $θ$ ₂>0

(Sin $θ$ ₁ – sin $θ$ ₂)( Sin $θ$ ₁ + sin $θ$ ₂)>0

Sin $θ$ ₁>sin $θ$ ₂ or ₁ >₂

T= $\frac{2 u s i n θ}{g} = \frac{2 v_{o} s i n θ}{g}$

T₁= $\frac{2 v_{o} s i n ϑ_{1}}{g}$ , T₂= $\frac{2 v_{o} s i n ϑ_{2}}{g}$

T₁> T₂

R= $\frac{u^{2} s i n 2 θ}{g} = \frac{v_{o}^{2} s i n 2 θ}{g}$

Sin $θ$ ₁>si

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Physics NCERT Exemplar Solutions Class 11th Chapter Four 2025

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