What should be the height of transmitting antenna and the population covered if the televition telecast is to cover a radius of 150 km? The average population density around the tower is 200 / km2 and the value of Re = 6.5 × 106 m.

Option 1 -

Height = 1800m                            

Population

...more

Option 2 -

Height = 1241m

Population Covered  = 7 * 105

Option 3 -

Height = 1600m

Population Covered = 2 * 105

Option 4 -

Height = 1731m

Population Covered = 1413 * 105

0 2 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    a month ago
    Correct Option - 4


    Detailed Solution:

    d = 150 km

    d = 2 h R

    h = d 2 2 R = ( 1 5 0 × 1 0 3 ) 2 2 × 6 . 5 × 1 0 6 = 1 7 3 1 m .

    Population covered

    π r 2 × σ = 3 . 1 4 × 1 5 0 2 × 2 0 0 0 = 1 4 1 3 × 1 0 5

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V
Vishal Baghel

According to question, we can write

  d = 2 h R d 2 d 1 = h 2 h 1 h 2 = ( d 2 d 1 ) 2 h 1 = ( 2 1 ) 2 × 1 2 5 = 5 0 0 m

Increment in height of tower = h2 – h1 = 500 – 125 = 375 m

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Low pass filter will allow low frequency signal to pass while high pass filter allow high frequency to pass through

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λ > h λ > 4 0 0 m

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Vishal Baghel

µ = A? /A? = 0.5 {A? = 20 volt, A? = 40 volt}
m (t) = A? sin ω? t {ω? = 2π×10? }
c (t) = A? sin ω? t {ω? = 2π×10×10³}
C? (t) = (A? + A? sin ω? t) sin ω? t ⇒ A? {1+ µsin ω? t} sin ω? t

V
Vishal Baghel

Kindly consider the following figure

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