When a ball is dropped into a lake form a height 4.9 m above the water level, it hits the water with a velocity v and then sinks to the bottom with the constant velocity v. It reaches the bottom of the lake 4.0 s after it is dropped. The approximate depth of the lake is
When a ball is dropped into a lake form a height 4.9 m above the water level, it hits the water with a velocity v and then sinks to the bottom with the constant velocity v. It reaches the bottom of the lake 4.0 s after it is dropped. The approximate depth of the lake is
Option 1 -
19.6 m
Option 2 -
29.4 m
Option 3 -
39.2 m
Option 4 -
73.5 m
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1 Answer
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Correct Option - 2
Detailed Solution:Total time (T) = 4 sec
Given u = 0 m/sec
a = g = 9.8 m/sec2
h = 4.9 m, t =?
t = 1 sec
‘v’ be the velocity with which ball hits the water v = u + at
= 0 + 9.8 × 1 = 9.8 m/sec
Time taken to reach the bottom of the lake from surface of the lake
= 4 – 1 = 3 sec
v = 9.8 m/sec
29.4 + 4.9 × 9 = 29.4 + 44.1
H = 73.5 m
Similar Questions for you
Let 't' be the time taken by B to meat A.
for A, u = 0
t = [2 + t]
h = 80m
a = 10 m/sec2
h = ut +
80 = 0 * t +
t + 2 = 4
t = 2sec
Now for B
h = ut +
Let ‘t’ be the time taken by B to meat

A.
for A, u = 0
t = [2 + t]
h = 80m
a = 10 m/sec2
h = ut +
80 = 0 × t +
16 = (2 + t)2
t + 2 = 4
t = 2sec
Now for B
h = ut +
80 = 2u + 5 × 2 × 2
80 = 2u + 20
2u = 60
u = 30m/sec
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