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CII Institute of Hospitality - ITC Gardenia, Bangalore admissions for all courses are currently ongoing. Interested candidates can apply in online mode through the official website. The online application process is explained in the following steps:

Step 1: Visit the official website of CII Institute of Hospitality - ITC Gardenia, Bangalore (ciiih.com/bangalore).

Step 2: Fill out the form.

Step 3: Complete the form and submit it.

Hello, GNM is a 3.5-year diploma-level programme according to the Indian Nursing Council (INC). This includes 3 years of classroom study with 6 months of mandatory internship in a healthcare facility.

Yes, applications are open at CII Institute of Hospitality - ITC Gardenia, Bangalore for various courses. The mode of application is online. Aspirants need to apply at the official website for admission to the various programme. Candidates can fill out the application form on the institute's official website.

For admission to Magadh University's BA (H) courses, students must possess the minimum qualification as prescribed by the university. As per the eligibility criteria, students who have completed Class 12 from a recognised board of India are eligible for the programme. Students note that the eligibility criteria may differ from college to college.

1.9. Average atomic mass = (Fractional abundance of ³⁵Cl x molar mass of ³⁵Cl) + (Fractional abundance of ³⁷Cl x molar mass of ³⁷Cl)

= (75.77/100 x 34.9689) + (24.23/100 x 36.9659)

= 26.4959 + 8.9568

= 35.4527

In order to get admission at CII Institute of Hospitality - ITC Gardenia, Bangalore, candidates must keep certain documents ready. Student can check the list of documents below:

• Scanned Class 10, Class 12 and graduation marksheet
• Leaving Certificate
• Aadhaar Card
• Passport-size photograph
• Signature

Note: The list of documents mentioned above are the general documents. For more details visit the official website.

2.7 Let the three capacitors be

$C_1$ = 2 pF, $C_2$ = 3 pF and $C_3$ = 4 pF

The equivalent capacitance, $C_{eq}$ is given by

$C_{eq}=C_1+C_2+C_3$ = 2 + 3 + 4 = 9 pF

$\left(b\right)$ When the combination is connected to a 100 V supply, the voltage in all three capacitors = 100 V

$\mathrm{T}\mathrm{h}\mathrm{e}$ charge in each capacitor is given by the relation, q = VC

Hence for $C_1$ , $q_1$ = 100 $*2pC$ = 200 pC = 2 $*{10}^{-10}$ C,

for $C_2$ , $q_2$ = 100 $*3pC$ = 300 pC = 3 $*{10}^{-10}$ C,

for $C_3$ , $q_3$ = 100 $*4pC$ = 400 pC = 4 $*{10}^{-10}$ C

Among paramedical degree holders, Nurse Anesthetist is one of the popular profiles. The highest salary offered to the CRNAs in India range from INR 10 LPA to INR 20 LPA. Impact Paramedical and Health Institute BSc graduates can also apply for the job profile. However, for selection, the degree holders will have to pass the selection rounds of the employer.

Boric acid contains planar BO₃^3- ions which are linked together through hydrogen bonding shown in the fig.

1.8. Mass percentage of Fe = 69.9%

Mass percentage of O = 30.1%

Hello, I believe you'll not face many difficulties, though having a PCB in Class 12 has its own advantages, but the GNM course syllabus is not that complex and provides foundational knowledge in Biology. If you are willing to put some extra effort, then you'll complete the course without any delays.

2.6 Capacitance of each of the three capacitors, C = 9 pF

The equivalent capacitance $C_{eq}$ when the capacitors are connected in series is given by

$\frac{1}{C_{eq}}$ = $\frac{1}{C}$ + $\frac{1}{C}+\frac{1}{C}$ = $\frac{3}{C}$ = $\frac{3}{9}$ = $\frac{1}{3}$

Hence,  $C_{eq}$ = 3 pF

Supply voltage, V = 120 V

Potential difference ( $V_1$ ) across each capacitor is given by $V_1$ = $\frac{V}{3}$ = $\frac{120}{3}$ = 40 V

Excess of CO₂ absorbs heat radiated by the earth. Some of it is dissipated into the atmosphere while the remaining part is radiated back to the earth. As a result, temperature of the earth increases. This is the cause of global warming.

1.7. 1 mole of CuSO₄ contains 1 mole (1 g atom) of Cu

Molar mass of CuSO₄= 63.5 + 32 + (4 x 16) = 159.5 g mol^-1

Thus, Cu that can be obtained from 159.5 g of CuSO₄ = 63.5 g

∴ Cu that can be obtained from 100 g of CuSO₄ =63.5/159.5 * 100  = 39.81g

The highly poisonous nature of CO arises because of its ability to form a complex with haemoglobin, which is about 300 times more stable than the oxygen-haemoglobin complex. This prevents haemoglobin in the red blood corpuscles from carrying oxygen round the body and ultimately resulting in death.

Since, anhydrous HF is a covalent compound and weak acid due to high bond dissociation energy. AlF₃does not dissolve in HF.
Whereas NaF is ionic compound.
3NaF + AlF₃ → Na₃ [AlF₆]
Na₃ [AlF₆] + 3BF₃ (g)→ AlF₃ + 3Na+ [BF]^–