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11 months agoContributor-Level 10
4.28. (a) Acetylene C2? H2? contains 3? bonds and 2? bonds.
(b) Ethylene C2? H4? contains 5? bonds and 1? bond.

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11 months agoContributor-Level 10
(a) H-COOH
CH3—COOH
CH3CH2—COOH
CH3CH2CH2—COOH
CH3CH2CH2CH2—COOH
(b) CH3COCH3
CH3COCH2CH3
CH3COCH2CH2CH3
CH3COCH2CH2CH2CH3
CH3CO (CH3)4CH3
(c) H—CH=CH2
CH3CH=CH2
CH3CH2CH=CH2
CH3CH2CH2CH=CH2
CH3CH2CH2CH2CH=CH2
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11 months agoNew Question
11 months agoContributor-Level 10
11.14
Butane is the longest chain.
Propane is principle chain and substituents are numbered accordingly.
Hexane is the longest chain. There are three -OH substituents and 2 methyl groups.
-OH of phenol is numbered a 1.
Propane is the principle chain and the alkoxy group is ethyl group.
the longest chain is pentane and substituents are numbered accordingly.
In such cases, cyclo groups are named first, followed by conventional naming methods.
The cyclo group is named first, followed by conventional naming methods.
Cyclo group is named first. Pentane having a double bond is named then with the suffix -OL added to the end.
The longest chain is buta
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11 months agoContributor-Level 10
(a) 2, 2-Demethylpentane
(b) 2, 4, 7-Trimethyloctane. For two alkyl groups on the same carbon its locant is repeated twice, 2, 4, 7-locant set is lower than 2, 5, 7.
(c) 2- Chloro-4-methylpentane. Alphabetical order of substituents, (d) But-3-yn-1-ol. Lower locant for the principal functional group, i.e., alcohol.
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11 months agoContributor-Level 10
As per the official website of DSMNRU, the shortlisting of candidates for the BCom programme is carried out based on marks secured in the accepted entrance test. The eligible candidates are those who have passed Class 12 in the relevent stream from a recognised board. Also, according to general knowledge, many universities and institutes accept students for BCom with an aggregate of 60% to 65% in Class 12. Candidates who are interested can consult the official website or the admissions office directly for more details.
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11 months agoContributor-Level 10
(a) Propylbenzene (b) 3-Methylpentanenitrite (c) 2, 5-Dimethylheptane
(d) 3-Bromo- 3-chloroheptane (e) 3-Chloropropanal (f) 2, 2-Dichloroethanol
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11 months agoContributor-Level 10
11.13
2,2,4-Trimethylpentan-3-ol
The naming of the compound usually starts with numbering the carbons in the chain. The lower set of locants are chosen for this purpose, while in this case numbering under this condition is done from the left side. Once the carbons are mentioned, the position of -OH group is numbered and -ol is added as the suffix.
2. 5-Ethylheptane-2,4-diol
Here the longest chain is the straight chain. For such situations, numbering should be such that the functional groups should be denoted by the smallest number. Ethyl group is named at the beginning as it's a side chain.
3. Butane-2,3-diol
In this system, gly
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11 months agoContributor-Level 10
Single bond contains only one sigma bond and double bond contains one sigma and one pi bond.

- In this structure, nine single bonds and three double bonds are present. So, there are 12σ and 3π bonds present.
- In this structure, eighteen single bonds are present. So, there are only 18σ bonds present.
- In this structure, four single bonds are present. So, there are only 4σ bonds present.
- In this structure, four single bonds and two double bonds are present. So, there are 6σ and 2π bonds present.
- In this structure, five single bonds and one double bond are present. So, there are 6σ and 1π bonds present.
- In thi
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11 months agoContributor-Level 10
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11 months agoContributor-Level 10
4.26. In BF3, B atom is sp2 hybridised. In NH3, N is sp3 hybridised.
After the reaction, hybridisation of B changes from sp2 to sp3, while the hybridisation of N remains the same.
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11 months agoContributor-Level 10
When N –propyl methyl ether reacts with HBr, it forms propanol and bromomethane, n- propyl methyl ether will cleave at O . and H+ will attack at O, and Br- will attack CH +
2. When Ethoxybenzene Reacts with HBr, it forms Phenol and bromoethane, Ethoxybenzene cleaves at H+ will attack at O, and Br- will attack
3. When nitrating mixture reacts with ethoxy benzene introduction of nitro group is occurred at para position as it will give the stable product without
4. As HI is a strong nucleophile it will protonate the oxygen, to form a good leaving And I- will attack at C (CH3)3+ to give tert- butyl iodide and ethanol
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11 months agoContributor-Level 7
To get admission in VITEEE Your chances are Low as of the cut of category 1 falls for 14200-14500 and your rank is significantly low that is clost to borderline.
You can Still try for VIT Bhopal and VIT -AP as backups and feel free to also try in VIT Vellore you should apply in Vit Vellore and bhopal as high preference
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11 months agoContributor-Level 10
4.25. Electronic configuration of 13Al in ground state= 1s2 2s2 2p6 3s2 3p1
Electronic configuration of 13Al in excited state = 1s2 2s2 2p6 3s1 3px13py1
Hence, hybridisation will be sp2 and this makes the geometry to be Trigonal planar (in case of AlCl3).
In AlCl–4, the empty 3pz orbital is also involved. So, the hybridisation is sp3 and the shape is tetrahedral
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11 months agoContributor-Level 10
11.11. Set (ii) is appropriate Because CH3Br is only a nucleophile whereas CH3ONa is nucleophile as well as strong base, so the elimination reaction can occur
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11 months agoContributor-Level 10
4.24. Hybridisation: It is defined as the process of intermixing of atomic orbitals of slightly different energies to give rise to new hybridized orbitals having equivalent energy and identical shapes.
Shapes of Orbitals:
sp hybridisation: When one s-and one p-orbital intermix then it is called sp-hybridisation. For example, in BeF2, Be atom undergoes sp-hybridisation. It has linear shape. Bond angle is 180°.
sp2 hybridisation: One s-and two p-orbitals get hybridised to form three equivalent hybrid orbitals. The three hybrid orbitals directed towards three corners of an equilateral triangle. It is, therefore, kno
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11 months agoContributor-Level 10
11.10 During Williamson synthesis of ethers, an alkyl halide reacts with an alkoxide (ion with –ve charge on the oxygen of alcohol and + ve charge on alkali metal like Na) ion. it is an SN2 reaction. In the reaction, alkyl halides should be least hindered. Hence, an alkyl halide is obtained from ethanol and alkoxide ion from 3-methylpentan-2-ol. The reactions are shown below:
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