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New Question

5 months ago

0 Follower 1 View

A
Akansha Bhandari

Contributor-Level 7

There has been no update on any changes in the JEE Advanced 2026 attempt limits. If any changes are to be made in the attempt limit, the same will be officially notified at jeeadv.ac.in. Currently, the JEE Advanced attempt limit is twice in two consecutive years.

New Question

5 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

4-ethoxycarbonylpent-3-enoic acid

New Question

5 months ago

0 Follower 3 Views

K
Krishnendu Chatterjee

Contributor-Level 10

Candidates can check the table below to know course-wise median package offered to UG 3-year, UG 4-year and PG 2-year:

Course  

Median Package (2022)

Median Package (2023)

Median Package (2024)

UG 3-year

INR 6 LPA

INR 8 LPA

INR 6.5 LPA

UG 4-year

0

INR 10 LPA

INR 6.5 LPA

PG 2-year

INR 7.95 LPA

INR 9.5 LPA

INR 9.5 LPA

New Question

5 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

h = a ( 1 + t 2 ) 2 . . . . . . . ( i )

k = at        ……… (ii)

From (i) & (ii) 2 h a = 1 + k 2 a 2  

required locus of Q is y2 = 2a (x – a/2)

Equation of directrix x – a/2 = -a/2Þ x = 0

New Question

5 months ago

0 Follower 5 Views

V
Vipra Mehra

Contributor-Level 7

IIT Roorke will start JEE Advanced registration 2026 on April 23, 2026 for Indian nationals. Application form will be available online on the website jeeadv.ac.in. The JEE Advanced application form 2026 for foreign nationals will be released on April 6, 2026

New Question

5 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

F e + 3 + l I 2 + F e + 2

Fe+2 undergoes reduction & I2 undergoes oxidation.

E c e l l o = E c a t h o d e o E a n o d e o

= (0.77 – 0.54) V = 0.23 V

 = 23 × 10-2 V

 x = 23

 x = 23

New Question

5 months ago

0 Follower 18 Views

V
Vishal Baghel

Contributor-Level 10

In S?2 reaction, inversion takes place, so configuration get reversed.

New Question

5 months ago

0 Follower 8 Views

N
Nishtha Sharma

Contributor-Level 9

The placement trends witnessed during JNU placement over the past three years are presented below:

Particulars  

UG 3-year Placement Statistics (2022)

UG 3-year Placement Statistics (2023)

UG 3-year Placement Statistics (2024)

Median package

INR 6 LPA

INR 8 LPA

INR 6.5 LPA

Total students

353

350

357

Students placed

21

25

30

Students selected for higher studies

332

325

327

Particulars  

UG 4-year Placement Statistics (2022)

UG 4-year Placement Statistics (2023)

UG 4-year Placement Statistics (2024)

Median package

0

INR 10 LPA

INR 6.5 LPA

Total students

0

75

78

Students placed

0

24

17

Students selected for higher studies

0

6

61

Particulars  

PG 2-year Placement Statistics (2022)

PG 2-year Placement Statistics (2023)

PG 2-year Placement Statistics (2024)

Median package

INR 7.95 LPA

INR 9.5 LPA

INR 9.5 LPA

Total students

1280

1329

1432

Students placed

86

12

188

Students selected for higher studies

384

1317

1244

 

New Question

5 months ago

0 Follower 3 Views

S
Saurabh Khanduri

Contributor-Level 10

Jadavpur University has been ranked among the best institutes for BSc courses. While certain similar institutes such as BHU and Jamia Milia are ranked higher than Jadavpur, the difference between them is very minor. Other similar institutes are ranked much lower than Jadavpur Univeristy. The aforemention rank comparison was performed using the NIRF ranks of all institutes.

New Question

5 months ago

0 Follower 5 Views

R
Raj Pandey

Contributor-Level 9

N 2 O 4 ? 2 N O 2

( 1 0 . 5 ) = 0 . 5 m o l 2 × 0 . 5 = 1 m o l

k P = ( 1 1 . 5 × 1 ) 2 ( 0 . 5 1 . 5 × 1 )

= 4 3 = 1 . 3 3

= 7 1 0 . 1 5 J / m o l

New Question

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

As Zn (OH)? , BeO, Al? O? are amphoteric, so they can react with both HCl and NaOH.

New Question

5 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Let total number of throws = n

Probability of getting 2 times = Probability of getting an even number 3 times.

   

[as probability of getting odd number = probability of getting even number = ]

Probability of getting an odd number for odd number of times =

 

          

New Question

5 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

When Ferric chloride reacts with potassium thiocyanate a blood red colour of Ferric thiocyanate is formed
FeCl? + 3KSCN → Fe (SCN)? + 3KCl

New Question

5 months ago

0 Follower 9 Views

M
Manori Karan

Contributor-Level 7

The exam date for JEE Advanced 2026 has been announced. IIT Roorkee is the organising institute for JEE Advanced exam 2026. The exam will be held on May 17, 2026.

New Question

5 months ago

0 Follower 5 Views

M
Mamona Majumder

Contributor-Level 10

IIT Roorkee is the organising institute for JEE Advanced 2026 exam. Details related to the exam date, eligibility criteria and syllabus of JEE Advanced 2026 can be checked on the website jeeadv.ac.in. 

New Question

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Formation of passive layer of Fe? O? on the surface of Fe and NO? gas is evolved
[Co (NH? )? ]³? is diamagnetic (t? g? eg? ) and is inner orbital complex

New Question

5 months ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

1000 ml solution contains 0.02 milli mole (mm)

500 ml solution contains 0.02 m.m

Solution made 1000 ml with H2O

m.m in final solution = 0.01 mm

Solution (A) + 0.01 m. m H2SO4

= 0.01 + 0.01

= 0.02 m.m

                             = 0.00002 × 103 mm

New Question

5 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

I (6)       F (8)

Case I       2            4

Case II      3            6

Case III     4            8

Total =   

 

New Question

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

i. Zn + 2NaOH → Na? ZnO? + H?
ii. 4Au + 8NaCN + O? + 2H? O → 4Na [Au (CN)? ]+ 4NaOH
iii. Cu + 4HNO? → Cu (NO? )? + 2NO? + 2H? O
(conc.)

New Question

5 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Δ H = 1 6 5 k J / m o l e

T =?

Δ S = 5 5 0 J K 1

At equilibrium Δ G = 0

T = Δ H Δ S = 1 6 5 × 1 0 0 0 5 5 0 K

= 3 × 1 0 0 K = 3 0 0 K

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