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The TalentSprint Hyderabad reports successful placements over the years. At present, over 700 companies are taking part in the placements 2024 and over 30,000 students have been placed in leading companies. For more information on TalentSprint Hyderabad placements 2024 refer to the table below:

4.25 Given:

Order of the reaction = 1

Let, Initial concentration [R]^°= x

Final concentration [R] = x/16

Rate constant k = 60 s^-1

We know, time

t= 2.303 / k log R₀ / R

t = 2.303 / 60 log (x/x/16)

t = 2.303 / 60s^-1 log (1/1/16)

t = 2.303 X log 16 / 60s^-1

Solving, we get t = 4.6 * 10^-2s

Yes, Cluster University Srinagar offers BCom and BCom (Hons) courses through its affiliated colleges. Apart from this, an integrated BCom course is also provided by the university. Admission to these programmes is based on performance in CUET. The students must also fulfil the course-specific eligibility requirements. 

The graduating students of TalentSprint Hyderabad are reported to have been placed in fortune companies across the globe. Check out the table below to know more about TalentSprint Hyderabad placement statistics:

No, both are different exams conducted by separate organisations. The full form of RRB NTPC is Railway Recruitment Board Non-Technical Popular Categories exam conducted for recruitment of Commercial Apprentice, Goods guard, Traffic Apprentice, Traffic Assistant, Assistant Station Master, etc. NTPC stands for National Thermal Power Corporation Limited.

The TalentSprint Hyderabad recorded a completion rate of 95% during the 2024 placement drive. The institute is known for its good placements that has been successful in placing graduating students over the years. Check out the table below for more information on TalentSprint Hyderabad placements for the year 2024

RRBs conducts various exams for recruitment to the post of Junior Engineers, Assistant Loco Pilot, Non-technical and popular category, Group, C/Group D, and other posts in departments and offices of Indian railways.

Candidates can apply now for admission to the BBA course at Dr. C.V. Raman University, Bihar. Currently, the admission portal for this year is open. Candidates can visit the official website of the university and can fill out the application form. Moreover, before applying for the course, candidates must ensure that they complete the basic eligibility criteria first. 

According to NIRF ranking 2024, SIMTS emerged to be as the top Dental college in India. Listed below are some colleges along with their rankings over the past three years:

4.24

(iv) As log [N₂O₅] vs time is a straight line given reaction is first Hence its rate law will be, Rate = k [N₂O₅]

(v) The slope of above graph is slope = 0.000209 K = 303 × slope

⇒4.82 × 10^-4sec^-1

Now, t_1/2 = 0.693/K.

⇒0.693/4.82 × 10^-4

⇒t_1/2 = 1438 sec. which is almost equal to (ii)

The TalentSprint Hyderabad is showing an impressive placement record as of now. Over 700 companies participate in the placement session. Check out the table for more information on TalentSprint Hyderabad placements 2024

Yes, Cluster University Srinagar select students based on performance in the Common University Entrance Test (CUET). Apart from this, candidates must be Class 12 or equivalent examination pass. The aspirants need to complete the CUET application procedure to apply. During form filling, Cluster University must be selected as a preference for admission. 

Directorate of Distance Education, Madurai Kamaraj University admission is done through merit based. Students qualify the eligibility criteria set by the university as per the course.

RRB NTPC full form stands for Railway Recruitment Boards Non-Technical Popular Categories. The exam is conducted for recruitment of eligible candidates for various graduate and undergraduate posts. The posts under RRB NTPC recruitment are Commercial Apprentice, Traffic Apprentice, Traffic Assistant, Goods Guard, Assistant Station Master, etc.

4.23 Radio active decay occurs via first order rate law,

t_1/2 = 5730 years. rate constant (k) of given decay is 0.693/t_1/2

⇒0.693/5730 = 1.2 × 10^-4 year^-1

By first order integrated rate law age of the sample will be,

T  = ( 2.303 / 1.2 X 10^-4 ) log (A₀/A_t)

where T is the age of the sample, A₀ is the initial activity of the sample. and A_t is the activity of the sample at any time t

T  = ( 2.303 / 1.2 X 10^-4 ) log (A₀/0.8 A₀)

T = 0.18 × 10⁴ years.

Age of given sample is 0.18 × 10⁴ years.