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Chandigarh University (CU) Punjab

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a month ago

How good is Chandigarh University for software engineering?

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Ridhima Sharma

Beginner-Level 3

Chandigarh University is a strong choice for software engineering due to its industry-oriented curriculum and hands-on learning approach. Students are trained in programming, software development, and system analysis using labs, live projects, and real-world tools. The university also provides specialised programs like CSE with IBM, which adds advanced training in AI, ML, and data analytics. Experienced faculty guide students through both theoretical and practical knowledge, supported by modern infrastructure including labs, libraries, and CU's LMS, where all content is digitally accessible. Regular workshops, seminars, and industry co

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a month ago

Chandigarh University (CU) Engineering

Which is better: Chemical Engineering or Computer Engineering at Chandigarh University?

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MANVI KHOSLA

Contributor-Level 6

Chandigarh University excels in both Chemical and Computer Engineering programs. Chemical Engineering provides solid foundations in process design, environmental engineering, and industrial applications. The programme includes practical labs and electives in petroleum and environmental engineering. Computer Engineering, meanwhile, focuses on software, systems, and data analytics, with options like the IBM-specialized CSE programme for students wanting deeper expertise in AI and analytics. With strong faculty, modern labs, and NIRF 31 ranking, CU ensures students in both fields are industry-ready. Students interested in tech, software,

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Chandigarh University (CU) Punjab

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a month ago

Is Chandigarh University for CS?

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Manasi

Beginner-Level 3

Yes, Chandigarh University is highly suitable for Computer Science studies. The university offers multiple specialised programs in CSE, BCA, and related fields, integrating modern technologies like AI, AR/VR, and data science. Labs are fully equipped for hands-on learning, and students can work on live projects and industry-oriented assignments. CU's programs are designed to balance theoretical knowledge with practical experience, allowing students to learn programming, software development, and data analytics while gaining exposure to tools like SQL, Python, and Tableau. The university also encourages participation in workshops, hacka

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Which is the best course at Chandigarh University: CSE or CSE with IBM?

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a month ago

Punjab Engineering

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Kartik Wadhwa

Beginner-Level 4

If you're looking at CSE at Chandigarh University, both programs are strong. The regular CSE course offers a comprehensive understanding of computer Science fundamentals, programming, and system design. In contrast, CSE with IBM is a globally recognised programme co-designed with IBM, featuring hands-on labs, experiential projects, and mentorship from IBM professionals. Students also get access to IBM's Learning Management System and practical exposure to industry tools and data analytics platforms. The IBM programme is ideal for those seeking specialised skills in AI, machine learning, and big data, whereas the standard CSE allows fle

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Bernoulli Principle Physics Mechanical Properties of Fluids

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a month ago

An ideal fluid of density 800kgm^-³, flows smoothly through a bent pipe (as shown in figure) that tapers in cross-sectional area from a to $\frac{a}{2} .$ The pressure difference between the wide and narrow sections of pipe is 4100 Pa. At wider section, the velocity of fluid is $\frac{\sqrt[]{x}}{6} m s^{- 1}$ for x = ________. (Given g = 10 ms^-²)

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Raj Pandey

Contributor-Level 9

$ρ = 800 k g / m^{3}$

P₁ – P₂ = 4100 Pa

Bernoulli’s question b/w (1) & (2)

$\frac{P_{1}}{ρ g} + \frac{v_{1}^{2}}{2 g} + z_{1} = \frac{P_{2}}{ρ g} + \frac{v_{2}^{2}}{2 g} + z_{2}$

⇒ $\frac{P_{1} - P_{2}}{ρ g} + \frac{v_{1}^{2}}{2 g} + 1 = \frac{v_{2}^{2}}{2 g} + 0$ -(1)

Equation of continuity

A₁v₁ = A₂v₂

v₂ = 2v₁ -(2)

from (1) & (2)

$\Rightarrow \frac{P_{1} - P_{2}}{ρ g} + \frac{v_{1}^{2}}{2 g} + 1 = \frac{{(2 v_{1})}^{2}}{2 g}$

$\frac{4100}{800 \times 10} + \frac{v_{1}^{2}}{2 g} + 1 = \frac{4 v_{1}^{2}}{2 g}$

$\frac{12100}{8000} = \frac{3 v_{1}^{2}}{2 g}$

$\Rightarrow v_{1}^{2} = \frac{2 \times 10}{3} \times \frac{12100}{8000}$

$= \frac{2}{3} \times \frac{121}{8}$

x = 363

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a month ago

Chemistry Class 12th

The structure of protein that is unaffected by heating is

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Chemistry Coordination Compounds Chemistry

Contributor-Level 10

Primary structure of protein in unaffected by physical or chemical changes.

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a month ago

The spin only magnetic moment value of an octhahedral complex among CoCl₃.4NH₃, NiCl₂.6H₂O and PtCl₄.2HCl, which upon reaction with excess of AgNO₃ gives 2 moles of AgCl is____________B. M. (Nearest integer)

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Block D and F Elements Chemistry

Contributor-Level 10

For precipitation of two moles of AgCl

Two Cl^- will produce as a free anion

CoCl₃.4NH₃ -> complex will $[C O {(N H_{3})}_{4} C l_{2}]$ Cl (will not give 2Cl^-)

$P t C l_{4} . 2 H C l \to$ complex will be H₂ [PtCl₆] will not any Cl^-

$N i C l_{2} . 6 H_{2} O \to [N i {(H_{2} O)}_{6}] C l_{2}$ will produce two Cl^- ion.

${[N i {(H_{2} O)}_{6}]}^{+ +} + 2 C l^{-} \to_{A g N O_{3}}^{} 2 A g C l (s)$ precipitate formation

$N i^{2 +} \to [A r] 3 d^{8} 4 s^{0}$

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New Question

a month ago

The spin- only magnetic moment value of the most basic oxide of vanadium among V₂O₃, V₂O₄ and V₂O₅ is _____________B. M (Nearest integer)

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Contributor-Level 10

Most basic oxide V₂O₃

Here V has +3 O.S. Hence V⁺³ -> $[A r] 3 d^{2}$

two unpaired e^- in d- subshell

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a month ago

Polymers Chemistry

Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R.

Assertion A : Dacron is an example of polyester polymer.

Reason R : Dacron is made up of ethylene glycol and terephthalic acid monomers.

In the light of the above statements, choose the most appropriate answer from the options given below.

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Contributor-Level 10

Kindly consider the following figure

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New Question

a month ago

Surface Chemistry Chemistry

2.0g of H₂ gas is adsorbed on 2.5g platinum powder at 300K and 1 bar pressure. The volume of the gas adsorbed per gram of the adsorbent is ______________mL.

(Given : R = 0.083 L bar K^-¹ mol^-¹)

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Physics NCERT Exemplar Solutions Class 11th Chapter Eleven Physics

Contributor-Level 10

Volume of H₂ adsorbed = $\frac{n R T}{P} = \frac{2 \times 0.083 \times 300}{2 \times 1} = 24.9 l i t = 24900 m l$

Therefore volume of gas adsorbed per gram of the adsorbent = $\frac{24900}{2.5} = 9960$

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New Question

a month ago

A 110 V, 50Hz, AC source is connected in the circuit (as shown in figure). The current through the resistance $55 Ω,$ at resonance in the circuit, will be__________A.

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Raj Pandey

Contributor-Level 9

At Resonance

X_L = X_C

then l_L = l_C

Now phasor diagram

for L & C

So, Net current = zero

$= (l_{L} + l_{C})$

Therefore current through R circuit at resonance will be zero

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New Question

a month ago

Amines Chemistry

In Friedel-Crafts alkylation of aniline, one gets

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Chemistry Chemical Kinetics Chemistry

Contributor-Level 10

Aniline show acid-base reaction with AlCl₃

aniline is a Lewis base while AlCl₃ acts as lewis acid.

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New Question

a month ago

A flask is filled with equal moles of A and B. The half lives of A and B are 100s and 50s respectively and are independent of the initial concentration. The time required for the concentration of A to be four times that of B is ______________s.

(Given : In 2 = 0.693)

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Haloalkanes and Haloarenes Chemistry

Contributor-Level 10

Process is based upon simultaneous disintegration hence,

$\frac{0.693}{100} \times t = 2.303 l o g_{10} \frac{A_{0}}{A_{t}}$ ………….(i)

and $\frac{0.693}{50} \times t = 2.303 l o g_{10} \frac{B_{0}}{B_{t}}$ ………….(ii)

from equation (i) and (ii)

$0.693 t [\frac{1}{50} - \frac{1}{100}] = [l o g \frac{B_{0}}{B_{t}} - l o g \frac{A_{0}}{A_{t}}] \times 2.303$

Here; A₀ = B₀ and $A_{t} = 4 \times B_{t}$

Therefore $0.693 t [\frac{1}{100}] = 2.303 [l o g (\frac{B_{0}}{B_{t}} \times \frac{A_{t}}{A_{0}})]$

$∴ t = \frac{2.303 \times 0.3010 \times 2 \times 100}{693} = 200 s$

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New Question

a month ago

Two isomers (A) and (B) with molar mass 184 g/mol and elemental composition C, 52.2%; H. 4.9% and Br 42.9% gave benzoic acid and p-bromobenzoic acid respectively on oxidation with KMnO₄. Isomer ‘A’ is optically active and gives a pale yellow precipitate when warmed with alcoholic AgNO₃. Isomer ‘A’ and ‘B’ are respectively

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New Question

a month ago

Equilibrium Chemistry

50 mL of 0.1 M CH₃COOH is being titrated against 0.1 M NaOH. When 25 mL of NaOH has been added, the pH of the solution will be_________× 10^-². (Nearest integer)

(Given : pKa (CH₃-COOH) = 4.76)

log 2 = 0.30

log 3 = 0.48

log 5 = 0.69

log 7 = 0.84

log 11 = 1.04

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Classification of Organic Compounds Chemistry Organic Chemistry

Contributor-Level 10

Here, total meq of acetic acid = 50 × 0.1 = 5

And total meq of NaOH = 25 × 0.1 = 2.5

After neutralization process

Meq of left acetic acid = 2.5

And meq of formed CH₃COONa = 2.5

$p H = p K a + l o g_{10} \frac{[S]}{[A]}$

$p H = 4.76 + l o g_{10} \frac{2.5}{2.5} = 4.76 = 476 \times 1 0^{- 2}$

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New Question

a month ago

Kindly go through the questions

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Jaypee Institute of Information Technology Centre for Distance and Online education, JIIT

Contributor-Level 10

With AlCl₃, alkyl halide will form cabocation which will show rearrangement.

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New Question

a month ago

Can I get admission in Centre for Distance and Online Education, JIIT for MBA with 60% in graduation?

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Shikha Arora

Contributor-Level 10

Candidates looking for admission at Centre for Distance and Online Education, JIIT must complete at least a graduation degree for the MBA course. Similarly, for the BBA course, aspirants must complete Class 12.

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New Question

a month ago

Physics Current Electricity Physics NCERT Exemplar Solutions Class 11th Chapter Eleven

As per the given circuit, the value of current through the battery will be__________A.

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Raj Pandey

Contributor-Level 9

$\begin{array}{l} D_{1} \\ D_{3} \end{array}}$ Forward biased offer zero Resistance

D₂} Reversed biased offers Infinite Resistance

$I = \frac{v}{R} = \frac{10}{10} = 1 A m p$

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New Question

a month ago

Colligative Properties and Molar Mass Chemistry Solutions

A 0.5 percent solution of potassium choride was found to freeze at -0.24°C. The percentage dissociation of potassium chloride is__________. (Nearest integer)

(Molal depression constant for water is 1.80 K kg mol^-¹ and molar mass of KCl is 74.6 g mol^-¹)

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