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Candidates willing to get admission must take part in the ISBR College admission process before the last date of application. Candidates must know their ISBR College eligibility criteria and apply accordingly. Follow the ISBR College application process mentioned below:

Step 1: Visit the official website of ISBR College.

Step 2: Select the required course.

Step 3: Pay the application fee.

Step 4: Fill out and submit the application form with required information.

The mode of ISBR College course admissions is online. The applicants will be shortlisted based on the consistency of the academic record, entrance scores, work experience (if any), versatility, and achievements. The admissions are based on the ISBR Aptitude Test, Micro Presentation,  and Personal Interview rounds. Candidates willing to get admission must first visit the official website of the college. Then, click on the Apply Now tab. Then, select the required course. Then, pay the application fee. Then, fill out and submit the application form with required information. 

When glass slab is not put in between lens and screen

$\frac{1}{v}-\frac{1}{u}=\frac{1}{f}$

$\Rightarrow \frac{1}{12}-\frac{1}{-240}=\frac{1}{f}......(1)$

When glass slab is put in between lens and screen

Shift = $t\left(1-\frac{1}{\mu }\right)=1\left(1-\frac{1}{1.5}\right)=\frac{1}{3}cm$

$\Rightarrow \frac{3}{35}-\frac{1}{-x}=\frac{1}{f}.........(2)$

With the help of equations (1) and (2), we can write

$\frac{3}{35}-\frac{1}{-x}=\frac{1}{12}-\frac{1}{-240}$

$\Rightarrow \left|\Delta u\right|=560-240=320cm=3.2m$

Candidates who have completed graduation in any discipline from a recognised university are eligible to apply for Post Graduate Certificate in Human Resource Management at XLRI Jamshedpur. Besides, aspirants should also have a minimum of 24 months of work experience after completing graduation to be eligible for this course. PGCHRM is a one-year course offered at XLRI Jamshedpur.

I doubt! The BSc Aviation eligibility criteria require Mathematics and Physics in Class 12, which is only possible if you are from the Science stream. Since this course has a strong focus on aeronautical Science or engineering, Mathematics and Physics basics are mandatory.

According to de-Broglie’s hypothesis, we can write

$\lambda =\frac{h}{p}=\frac{h}{\sqrt[]{2meV}}$

$\Rightarrow \frac{{\lambda }_P}{{\lambda }_D}=\frac{\sqrt[]{2m_{D}e{V}_D}}{\sqrt[]{2m_{P}e{V}_P}}=\frac{1}{\sqrt[]{2}}\Rightarrow \frac{2m_P{V}_D}{m_P{V}_P}=\frac{1}{2}\Rightarrow \frac{V_P}{V_D}=4:1$

Candidates should have passed MBA/ PGDM or equivalent or GMP/ PGPX or one year full-time residential programme in Management with at least 60% marks to apply for FPM programme at XLRI Jamshedpur. Additionally, candidates must also be employed in a full-time job. Aspirants should also have at least 5 years of full-time executive/ managerial/ teaching/ research experience.

$C_1=4\pi R_{1}and$

$C_2=\frac{4\pi R_2{R}_1}{R_2-R_1}=\frac{R_2{C}_1}{R_2-R_1}$

$\Rightarrow \frac{C_2}{C_1}=\frac{4\pi R_2{R}_1}{R_2-R_1}=\frac{R_2}{R_2-R_1}=n$

$\Rightarrow \frac{R_2}{R_1}=\frac{n}{n-1}$

Though it's important to check the required documents list from the college's official website, here are some essential things you must carry during BSc Aviation application process:

• Class 10 and 12 mark sheets
• Passport-sized photographs
• Valid photo ID proof (Adhaar, PAN card, passport, etc.)
• Migration certificate, etc.

The college life for outstation stations is quite interesting. ISBR College has a state-of-the-art infrastructure with multiple facilities available in the college. ISBR offers stress-free learning classrooms, board rooms, seminar halls, discussion rooms, and others. The college has a Knowledge Centre, Communications and Broadband-enabled Wi-Fi campus, Library, Audio Video Media Room, and others.

Let additional force is $\overrightarrow{F}$ , so

$\overrightarrow{F}+5\left(+\widehat{i}\right)+6\left(-\widehat{i}\right)+7\left(+\widehat{j}\right)+8\left(-\widehat{j}\right)=\overrightarrow{0}$

$\Rightarrow \overrightarrow{F}-\left(\widehat{i}+\widehat{j}\right)=\overrightarrow{0}\Rightarrow \overrightarrow{F}=\widehat{i}+\widehat{j}\Rightarrow F=\sqrt[]{2}N,45°$

$\Delta p$ = Change in momentum of each ball

$\Delta p=2mv=2\times 0.05\times 10=1Ns$

$\Rightarrow F=\frac{\Delta p}{\Delta t}=\frac{2\times 0.05\times 10}{0.005}=200N$

Since liquid drop is in equilibrium, so

mg = F_B + 2πRT

$\Rightarrow \frac{4}{3}\pi R^3\rho g=\frac{2}{3}\pi R^3\sigma g+2\pi RT$

$\Rightarrow R=\frac{3T}{\left(2\rho -\sigma \right)g}=\frac{15}{\sqrt[]{\left(2\rho -\sigma \right)}}\times 10^{-2}m=\frac{15}{\sqrt[]{\left(2\rho -\sigma \right)}}cm$

$B_1=\frac{N_1{\mu }_{0}l}{2R}$ given N1 = 2

When new loop is made the length of wire remains same, so

$N_2\times 2\pi r=N_1\times 2\pi R\Rightarrow r=\frac{N_{1}R}{N_2}$

$\Rightarrow \frac{B_2}{B_1}={\left(\frac{N_2}{N_1}\right)}^2=\frac{25}{4}$

Modulation index = $\frac{A_{max}-A_{min}}{A_{max}+A_{min}}=\frac{6-2}{6+2}=0.5\approx 50\mathrm{\%}$

The correction window for GATE 2026 will open 1 to 2 weeks after the completion of GATE application form. The exact dates will be notified on the GATE's 2026 official website. During this period, candidates can make specific edits by paying a certain amount of fees. 

Yes, candidates seeking admission in the BTech programme of IIIT Delhi must have a valid JEE Main score. The cutoff is usually less competitive for IIIT Delhi. The highest cutoff scores usually is of Computer Science Engineering. Candidates based on their JEE Main score are allotted seats through JAC Delhi Counselling. In 2024, the JEE Main cutoff for CSE was 6695.