8.7 The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B0 = 510 nT. What is the amplitude of the electric field part of the wave?

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Physics Ncert Solutions Class 12th Physics Class 12th Electromagnetic Waves

8.7 The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B₀ = 510 nT. What is the amplitude of the electric field part of the wave?

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Payal Gupta | Contributor-Level 10

5 months ago

8.7 The amplitude of magnetic field of the electromagnetic wave in a vacuum,

$B_{0}$ = 510 nT = 510 $* 10^{- 9}$ T

Speed of the light in vacuum, c = 3 $* 10^{8}$ m/s

Amplitude of electric field of the electromagnetic wave is given by the relation,

E = c $B_{0}$ = 3 $* 10^{8} *$ 510 $* 10^{- 9}$ N/C = 153 N/C

Hence, the electric field part of the wave is 153 N/C.

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8.7 The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B₀ = 510 nT. What is the amplitude of the electric field part of the wave?

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