A ball is projected with kinetic energy E, at an angle of 60° to the horizontal. The kinetic energy of this ball at the highest point of its flight will become:

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Physics NCERT Exemplar Solutions Class 12th Chapter Nine Physics NCERT Exemplar Solutions Class 12th Chapter Four Physics Class 12th Motion in a Plane

A ball is projected with kinetic energy E, at an angle of 60° to the horizontal. The kinetic energy of this ball at the highest point of its flight will become:

Option 1 -

zero

Option 2 -

$\frac{E}{2}$

Option 3 -

$\frac{E}{4}$

Option 4 -

4 Views | Posted 2 months ago

Asked by Shiksha User

1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

2 months ago

Correct Option - 3

Detailed Solution:

$E = \frac{1}{2} m u^{2}$

$E_{H i g h e s t p o i n t} = \frac{1}{2} m {(\frac{u}{2})}^{2} = \frac{1}{8} m u^{2} = \frac{E}{4}$

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A ball is projected with kinetic energy E, at an angle of 60° to the horizontal. The kinetic energy of this ball at the highest point of its flight will become:

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