Can reflection result in plane polarised light if the light is incident on the interface from the side with higher refractive index?

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- When angle of incidence is equal to Brewster’s angle, the transmitted light is unpolarised and reflected light is plane polarised.

Consider the diagram in which unpolarised light is represented by dot and plane polarised light is represented By arrows.

Polarisation by reflection occurs when the angle of incidence Is the Brewster’s angle

So tani_b = $\frac{{\mu }_1}{{\mu }_2}$  where $\mu$ ₂< $\mu$ ₁

When the light rays travels in such a medium, the critical angle is

Sini_c= $\frac{{\mu }_2}{{\mu }_1}$

Where $\mu$ ₂< $\mu$ ₁

As tani_b > sini_c for large angles i_bc

Thus the polarisation by reflection occurs definitely.

<p>This is a Short Answer Type Questions as classified in NCERT Exemplar</p><p><strong>Explanation- </strong>When angle of incidence is equal to Brewster’s angle, the transmitted light is unpolarised and reflected light is plane polarised.</p><div><div><picture><source srcset="https://images.shiksha.com/mediadata/images/articles/1743138484php8mDqeI_480x360.jpeg" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/articles/1743138484php8mDqeI.jpeg" alt="" width="216" height="187"></picture></div></div><p>Consider the diagram in which unpolarised light is represented by dot and plane polarised light is represented By arrows.</p><p>Polarisation by reflection occurs when the angle of incidence Is the Brewster’s angle</p><p>So tani_b =<span contenteditable="false"> <math> <mfrac> <mrow> <mrow> <msub> <mrow> <mrow> <mi>μ</mi> </mrow> </mrow> <mrow> <mrow> <mn>1</mn> </mrow> </mrow> </msub> </mrow> </mrow> <mrow> <mrow> <msub> <mrow> <mrow> <mi>μ</mi> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msub> </mrow> </mrow> </mfrac> </math> </span>&nbsp;where<span contenteditable="false"> <math> <mi>μ</mi> </math> </span> ₂&lt;<span contenteditable="false"> <math> <mi>μ</mi> </math> </span>₁</p><p>When the light rays travels in such a medium, the critical angle is</p><p>Sini_c=<span contenteditable="false"> <math> <mfrac> <mrow> <mrow> <msub> <mrow> <mrow> <mi>μ</mi> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msub> </mrow> </mrow> <mrow> <mrow> <msub> <mrow> <mrow> <mi>μ</mi> </mrow> </mrow> <mrow> <mrow> <mn>1</mn> </mrow> </mrow> </msub> </mrow> </mrow> </mfrac> </math> </span></p><p>Where <span contenteditable="false"> <math> <mi>μ</mi> </math> </span>₂&lt;<span contenteditable="false"> <math> <mi>μ</mi> </math> </span>₁</p><p>As tani_b &gt; sini_c for large angles i_bc</p><p>Thus the polarisation by reflection occurs definitely.</p>

0 Upvotes 0 Upvotes 0 Downvotes

• • Report Abuse
• Comment