Starting from the origin at time , with initial velocity , a particle moves in the plane with a constant acceleration of . At time , its coordinates are . The values of and are, respectively:
Starting from the origin at time , with initial velocity , a particle moves in the plane with a constant acceleration of . At time , its coordinates are . The values of and are, respectively:
Option 1 - <p><math><mn>2</mn><mtext></mtext><mi mathvariant="normal">s</mi></math> and <math><mn>24</mn><mtext></mtext><mi mathvariant="normal">m</mi></math></p>
Option 2 - <p><math><mn>4</mn><mtext></mtext><mi mathvariant="normal">s</mi></math> and <math><mn>52</mn><mtext></mtext><mi mathvariant="normal">m</mi></math></p>
Option 3 - <p> <math><mn>5</mn><mtext></mtext><mi mathvariant="normal">s</mi></math> and <math><mn>25</mn><mtext></mtext><mi mathvariant="normal">m</mi></math></p>
Option 4 - <p> <math><mn>2</mn><mtext></mtext><mi mathvariant="normal">s</mi></math> and <math><mn>18</mn><mtext></mtext><mi mathvariant="normal">m</mi></math></p>
4 Views|Posted 6 months ago
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6 months ago
Correct Option - 4
Detailed Solution:
Similar Questions for you
Given A = B
Squaring equation (1) both side.
2A2 + 2A2 cosq = 4 (2A2 – 2A2 cosq)
2A2 + 2A2 cosq = 8A2 – 8A2 cosq
10A2 cosq = 6A2
cosq =
q = cos-1 (3/5)
Component of along =
= 2
y = x5 (1 - x) = x tanθ
tan = 5, R = 1
y - component of initial velocity
= u sinθ
=
= 5 m/s
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Physics NCERT Exemplar Solutions Class 12th Chapter Four 2025
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