The amplifiers X, Y and Z are connected in series. If the voltage gains of X, Y and Z are 10,20 and 30, respectively and the input signal is 1 mV peak value, then what is the output signal voltage (peak value).
(i) If DC supply voltage is 10 V?
(ii) If DC supply voltage is 5 V?

<p>This is a &nbsp;Short Answer Type Questions as classified in NCERT Exemplar</p><p><strong>Explanation-&nbsp;</strong>as we know total voltage amplification =<span contenteditable="false"> <math> <mfrac> <mrow> <mrow> <mi>o</mi> <mi>u</mi> <mi>t</mi> <mi>p</mi> <mi>u</mi> <mi>t</mi> <mi> </mi> <mi>s</mi> <mi>i</mi> <mi>g</mi> <mi>n</mi> <mi>a</mi> <mi>l</mi> <mi> </mi> <mi>v</mi> <mi>o</mi> <mi>l</mi> <mi>t</mi> <mi>a</mi> <mi>g</mi> <mi>e</mi> </mrow> </mrow> <mrow> <mrow> <mi>i</mi> <mi>n</mi> <mi>p</mi> <mi>u</mi> <mi>t</mi> <mi> </mi> <mi>s</mi> <mi>i</mi> <mi>g</mi> <mi>n</mi> <mi>a</mi> <mi>l</mi> <mi> </mi> <mi>v</mi> <mi>o</mi> <mi>l</mi> <mi>t</mi> <mi>g</mi> <mi>e</mi> </mrow> </mrow> </mfrac> </math> </span></p><p>Av_x= 10, Av_y= 20, Av_z= 30</p><p><span contenteditable="false"> <math> <mo>? </mo> </math> </span>v_i = 1mV= 10^-3V</p><p>So according to formula</p><p>&nbsp;= (Av_x ) (Av_y ) (Av_z)</p><p><span contenteditable="false"> <math> <mo>? </mo> </math> </span>v_o =&nbsp; (Av_x ) (Av_y ) (Av_z)<span contenteditable="false"> <math> <mo>? </mo> </math> </span> v_i</p><p>&nbsp; = 10^{-3<span contenteditable="false"> <math> <mo>×</mo> <mn>20</mn> <mo>×</mo> <mn>30</mn> <mo>×</mo> <mn>10</mn> </math> </span>} =6V</p><p>So in first case output cannot be greater than 6V but in 2^nd case it will work</p>

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